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sleet_krkn [62]
2 years ago
13

A 10.-liter flask at a given temperature and pressure contains 6.0 × 1023 molecules of hydrogen gas. Under the same conditions o

f temperature and pressure, how many molecules would a 10.-liter flask of nitrogen gas contain?
Chemistry
1 answer:
valentina_108 [34]2 years ago
6 0

Answer:

The same number of molecules, 6.0 × 10²³ molecules.

Explanation:

The amount of any given gas that can be stored in a container depends on the <u>temperature, pressure and volume </u>of the container. It does not depend on the nature (or identity) of the gas.

So if a 10-liter flask contains 6.0 × 10²³ molecules of hydrogen gas, it will contain the same amount of molecules of any other gas when temperature and pressure remain constant.

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Hexane and heptane are miscible with each other in all proportions. In making a solution of them, is the entropy of the system i
Damm [24]

Answer: Option (a) is the correct answer.

Explanation:

A miscible solution is defined as the one in which two or more than two components are soluble with each other.

So, when hexane is added to heptane then both of them will mix with each other and hence they are miscible. This mixing will lead to formation of more number of ions into the solution as a result, more will be the disorder present in the solution.

As entropy is the degree of randomness present.

Hence, we can conclude that a solution of hexane and heptane will lead to an increase in entropy.

8 0
3 years ago
PLZ HELP, GIVING BRANLIEST!!
valentinak56 [21]

Answer:

Option A. The polar solvent molecule surrounds the positive sodium ions and the negative chloride ions.

Explanation:

When a salt say NaCl dissolved in water, the solvent molecules surround both the Na+ and Cl-. The Na+ are surrounded by OH- and the Cl- are surrounded by H+.

5 0
3 years ago
What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?
RideAnS [48]

Answer:

Explanation:

Na + Cl2 —> NaCl

8 0
2 years ago
A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?
kari74 [83]

Answer:

5.7 moles of O2

Explanation:

We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.

Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.

Thus, 5.7 moles of O2 were obtained from the reaction.

3 0
2 years ago
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elena-s [515]

Answer:

the answer to number 9 is A.

Explanation:

6 0
2 years ago
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