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zhuklara [117]
3 years ago
8

Susan makes the following entry in her notebook: “On Friday we were given a blue liquid in a shallow container. We placed it on

the windowsill over the weekend. On Monday morning, there was no liquid left, but the dish had some solid blue stuff in it.”
a. Was the blue liquid in the dish a heterogenous mixture, a solution, or a pure substance? Explain your choice.

b. Write a few sentences about what you think happened in the dish.
Physics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

Explanation:

a. From the information provided in the question, the blue liquid is a solution. This is because a solution is a type of homogeneous mixture (that has an evenly distributed solute in a solvent) which is the reason the liquid was said to be blue (and not immiscible blue solid in a liquid) but after been exposed to heat became just a blue solid. Typically, a solution has a solute and a solvent (combined), the solute here is the blue solid while the solvent is the liquid that made the combination a liquid.

b. Since the dish containing the liquid was placed on a windowsill, it can be assumed that the dish was subjected to heat from the sun which caused the liquid (in the solution) to evaporate after exposure to the heat from the sun (over the weekend) leaving the blue solid solute (of the solution) to remain in the dish. This can be referred to as evaporation to dryness in separation techniques (if the goal was to intentionally separate the solid solute from the liquid solvent).

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gregori [183]

Answer:

1. 0.625 g/mL

2. 2×10⁵ J

3. 5040 J

4. 75000 J

Explanation:

1. Determination of the density.

We'll begin by calculating the volume of the marble. This can be obtained as follow:

Volume of water = 60 mL

Volume of water + Marble = 68 mL

Volume of marble =?

Volume of marble = (Volume of water + Marble) – (Volume of water)

Volume of marble = 68 – 60

Volume of marble = 8 mL

Finally, we shall determine the density of the marble. This can be obtained as follow:

Mass of marble = 5 g

Volume of marble = 8 mL

Density of marble =?

Density = mass / volume

Density of marble = 5 / 8

Density of marble = 0.625 g/mL

2. Determination of the work done.

Mass (m) = 1000 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 10 m/s²

Workdone (Wd) =?

The work done can be obtained as follow:

Wd = mgh

Wd = 1000 × 10 × 20

Wd= 2×10⁵ J

3. Determination of the potential energy.

Mass (m) = 12 Kg

Height (h) = 42 m

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) =?

The potential energy can be obtained as follow:

PE = mgh

PE = 12 × 10 × 42

PE = 5040 J

4. Determination of the kinetic energy.

Mass (m) = 1500 Kg

Velocity (v) = 10 m/s

Kinetic energy (KE) =?

The kinetic energy can be obtained as follow:

KE = ½mv²

KE = ½ × 1500 × 10²

KE = 750 × 100

KE = 75000 J

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What is the accleration of a car that travels 10 meters in 2seconds
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