Answer:
The distance away the center of the earthquake is 1083.24 km.
Explanation:
Given that,
Speed of transverse wave = 9.1\ km/s
Speed of longitudinal wave = 5.7 km/s
Time = 71 sec
We need to calculate the distance of transverse wave
Using formula of distance
....(I)
The distance of longitudinal wave
....(II)
From the first equation
Put the value of t in equation (II)
Hence, The distance away the center of the earthquake is 1083.24 km.
Answer:
um, when you talk with other people about stuff. (I'm not trying to sound like a smarta s s I'm just giving a definition...)
Explanation:
Answer:
a) a = 1,865 m / s² and b) t = 8.1 s
Explanation:
a) Let's use Newton's second law to find acceleration, we can work the equation in scalar form because displacement and force have the same direction
F = m .a
a = F / m
a = 8.02 10² /4.3 10²
a = 1,865 m / s²
b) We use kinematic relationships in one dimension
vf = vo + at
vf = 0 + a t
t = vf / a
t = 15.1 / 1.865
t = 8.1 s
Answer:
P₁ = 2.215 10⁷ Pa, F₁ = 4.3 106 N,
Explanation:
This problem of fluid mechanics let's start with the continuity equation to find the speed of water output
Q = A v
v = Q / A
The area of a circle is
A = π r² = π d² / 4
Let's look at the speeds at each point
v₁ = Q / A₁ = Q 4 /π d₁²
v₁ = 10 4 /π 0.5²
v₁ = 50.93 m / s
v₂ = Q / A₂
v₂ = 10 4 /π 0.25²
v₂ = 203.72 m / s
Now we can use Bernoulli's equation in the colon
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear
P₁ = P2 + ½ rho (v₂² - v₁²)
P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)
P₁ = 1.013 10⁵ + 2.205 10⁷
P₁ = 2.215 10⁷ Pa
la definicion de presion es
P₁ = F₁/A₁
F₁ = P₁ A₁
F₁ = 2.215 10⁷ pi d₁²/4
F₁ = 2.215 10⁷ pi 0.5²/4
F₁ = 4.3 106 N