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S_A_V [24]
2 years ago
10

Why do atoms of different elements vary in size?

Chemistry
2 answers:
Usimov [2.4K]2 years ago
7 0

Answer:

As you go down the periodic table, usually atoms get bigger because n gets bigger (there are electrons in higher shells). Effective nuclear charge does get bigger too going down the periodic table, but this effect is smaller than the change in shell.

Explanation:

Zinaida [17]2 years ago
3 0
As you go down the periodic table, usually atoms get bigger because n gets bigger (there are electrons in higher shells). Effective nuclear charge does get bigger too going down the periodic table, but this effect is smaller than the change in shell.
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Please help me out i don’t get this. what is the answers to 1-4.
VLD [36.1K]

Answer:

1. A circuit is a path that electricity flows along. It starts at a power source, like a battery, and flows through a wire to a light bulb or other object and back to other side of the power source.

2. A series circuit is one that has more than one resistor, but only one path through which the electricity (electrons) flows. All the components in a series circuit are connected end-to-end. A resistor in a circuit is anything that uses some of the power from the cell.

3. A parallel circuit is a circuit in which the electric current passes through two or more branches or connected parts at the same time before it combines again. Compare.

4. BOTH - 1. lightbulb 2. battery 3. switch

   SERIES- 1. Ammeter 2. voltmeter

i'm not sure about the rest sorry :(

7 0
3 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
Describe the changes in properties (from metals to nonmetals or from nonmetals to metals) as we move (a) down a periodic group a
defon

Answer:

Explanation:

The changes in properties from metals to non-metals on a periodic table can be measured and determined by the metallicity or electropositivity of elements.

Metallicity is a measure of the tendency of atoms of an element to lose electrons.

a.

Down a periodic group, metallicity increases.

b.

Across a period from left to right electropositivity or metallicity decreases.

Metals are found in the left part of periodic table and the most reactive metal sits in the lower left corner. Non-metals are towards the right side of the table.

7 0
3 years ago
Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction
AVprozaik [17]

Answer:

The volume of the flask is<u> 20.245 litres .</u>

Explanation:

We are given with following information-

PV=nRT -------- 1

where R =0.0821L.atom/mole.K

Molar mass of PCl_5=208.22g/mole

The given chemical equation is -

2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5  _(_s_) --------- 2

Now , calculation -

Mass of PCl_5 formed = 118g

Molar mass of PCl_5 = 208.22g/mole

      Mole = \frac{mass (g)}{molar mass}

Therefore , moles of PCl_5 formed = \frac{118}{208.22}

     From equation 2 , we get to know that ,

 2mole PCl_5 formed from 5 mole Cl_2 _(_g_)

Therefore , \frac{118}{208.22} mole PCl_5 formed from \frac{5}{2} \times\frac{118}{208.22} mole Cl_2 _(_g_)

Moles of Cl_2 _(_g_) used =\frac{5\times118}{2\times208.22} mole

R= 0.0821L.atom/mole.K

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  Cl_2 _(_g_) (n)= \frac{5}{2} \times\frac{118}{208.22} moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322

 V = 20.245 litres.

Hence , the volume of the flask is <u>20.245 litres . </u>

 

8 0
3 years ago
2H2(g) + O2(g) mc001-1.jpg 2H2O(g)
Aleks [24]
The answer is a) by increasing the temperature of the reactants.
6 0
3 years ago
Read 2 more answers
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