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ch4aika [34]
3 years ago
4

Explain the major differences between designing buildings for earthquake resistance and for wind resistance.

Engineering
1 answer:
True [87]3 years ago
6 0

Answer:

Earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.

Explanation:

The most important difference between the design of a building that's resistent to earthquakes and resistant to high speed winds is that earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.

Earthquake resistent building are equipped with a base that is isolated from the buildings with several layers of different material which absorb the vibration of the seismic waves and prevent them from reaching to the building.

Wind resistent buildings must have strong foundations and a sturdy structure/material that can withstand high pressure that the wind applies during events such as hurricanes.

I hope this answer helps.  

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A 3.52 kg steel ball is tossed upward from a height of 6.93 meters above the floor with a vertical velocity of 2.99 m/s. What is
Dafna1 [17]

Answer : The final velocity of the ball is, 12.03 m/s

Explanation :

By the 3rd equation of motion,

v^2-u^2=2as

where,

s = distance covered by the object = 6.93 m

u = initial velocity  = 2.99 m/s

v = final velocity = ?

a = acceleration = 9.8m/s^2

Now put all the given values in the above equation, we get the final velocity of the ball.

v^2-(2.99m/s)^2=2\times (9.8m/s^2)\times (6.93m)

v=12.03m/s

Thus, the final velocity of the ball is, 12.03 m/s

7 0
3 years ago
A crankcase heater is often used to prevent refrigerant from mixing with compressor oil during periods of:
stira [4]

Answer:

Low ambient temperature

Explanation:

Hope this helps. If it did, please mark as brianliest so other people see it. Thanks! - Kai

5 0
3 years ago
Read 2 more answers
Why is the reflection step in the engineering process the most important step?
Monica [59]
Reflection helps designers to learn from their experiences, to integrate and co-ordinate different aspects of a design situation, to judge the progress of the design process, to evaluate interactions with the design context, and to plan suitable future design activities.
6 0
3 years ago
It has a piece of 1045 steel with the following dimensions, length of 80 cm, width of 30 cm, and a height of 15 cm. In this piec
Serggg [28]

Answer:

material remove in 3 min is 16790.4 mm³/s

Explanation:

given data

length L = 80 cm = 800 mm

width W = 30 cm

height H = 15 cm

make grove length = 80 cm

width = 8 cm

depth = 10 cm

mill toll diameter = 4 mm

axial cutting depth = 20 mm

to find out

How much material removed in 3 minutes

solution

first we find time taken for length of advance that is

time = \frac{length}{advance}

here advance is given as 0.001166 mts / sec

so  time = \frac{800}}{0.001166*1000}

time = 686.106 seconds

now we find material remove rate that is

remove rate = mill toll rate × axial cutting depth × advance

remove rate = 4 × 20×0.001166 ×1000

remove rate = 93.28 mm³/s

so

material remove in 3 minute = 3 × 60 = 180 sec

so material remove in 3 min = 180 × 93.28

material remove in 3 min is 16790.4 mm³/s

7 0
3 years ago
The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of h
diamong [38]

Answer:

M=0.0411 kg/h or 4.1*10^{-2} kg/h

Explanation:

We have to combine the following formula to find the mass yield:

M=JAt

M=-DAt(ΔC/Δx)

The diffusion coefficient : D=6.0*10^{-8} m/s^{2}

The area : A=0.25 m^{2}

Time : t=3600 s/h

ΔC: (0.64-3.0)kg/m^{3}

Δx: 3.1*10^{-3}m

Now substitute the  values

M=-DAt(ΔC/Δx)

M=-(6.0*10^{-8} m/s^{2})(0.25 m^{2})(3600 s/h)[(0.64-3.0kg/m^{3})(3.1*10^{-3}m)]

M=0.0411 kg/h or 4.1*10^{-2} kg/h

8 0
3 years ago
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