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stira [4]
3 years ago
13

Which occurs within a high pressure system?

Chemistry
2 answers:
alina1380 [7]3 years ago
4 0

Answer:

Dense air is pushed downwards towards the surface. since the air is being pushed down the air above spreads and thats when "fair wheather" happens.

Explanation:

Hope that helped!

blsea [12.9K]3 years ago
3 0

Answer:

A high pressure system has higher pressure at its center than the areas around it. Winds blow away from high pressure. Swirling in the opposite direction from a low pressure system, the winds of a high pressure system rotate clockwise north of the equator and counterclockwise south of the equator.

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1.034 g of a metal sulfate hydrate (if you have not heard of hydrates, look up online or in your lecture course textbook) was he
OverLord2011 [107]

Answer:

7.54%

Explanation:

A hydrate is a salt that has molecules of water incorporated into the crystals. It is represented by the molecular formula of the salt followed by how many molecules of water it has: XY.nH₂O.

So, the mass of water in the sample will be the difference between the hydrate and the salt without water:

mass of water = 1.034 - 0.956 = 0.078 g

The mass percentage is the mass of water divided by the total mass, and then multiplied by 100%:

(0.078/1.034)x100%

7.54%

3 0
3 years ago
What is the possible formula of AC if A has 2 valence electrons and C has 7 valence electron?
Brut [27]
AC2

A will lose 2
C will gain 1

Need two Cs to match A
3 0
3 years ago
Wasting my points here who wants them?
yKpoI14uk [10]
Me thanks for the points
4 0
2 years ago
Read 2 more answers
Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.Express your answer to two significant f
N76 [4]

The question is incomplete, here is the complete question:

Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction

A + 2B ⇔ C

whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:

The table is attached below as an image.

<u>Answer:</u> The initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+2B\rightleftharpoons C

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

  • Expression for rate law for first trial:

5.4\times 10^{-3}=k(0.30)^a(0.050)^b ....(1)

  • Expression for rate law for second trial:

1.1\times 10^{-2}=k(0.30)^a(0.100)^b ....(2)

  • Expression for rate law for third trial:

2.2\times 10^{-2}=k(0.50)^a(0.050)^b ....(3)

Dividing 2 by 1, we get:

\frac{1.1\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.30)^a(1.00)^b}{(0.30)^a(0.050)^b}\\\\2=2^b\\b=1

Dividing 3 by 1, we get:

\frac{2.2\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.50)^a(0.050)^b}{(0.30)^a(0.050)^b}\\\\4.07=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^1       ......(4)

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

5.4\times 10^{-3}=k[0.30]^2[0.050]^1\\\\k=1.2M^{-2}s^{-1}

Calculating the initial rate of formation of C by using equation 4, we get:

k=1.2M^{-2}s^{-1}

[A] = 0.50 M

[B] = 0.075 M

Putting values in equation 4, we get:

\text{Rate}=1.2\times (0.50)^2\times (0.075)^1\\\\\text{Rate}=2.25\times 10^{-2}Ms^{-1}

Hence, the initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

8 0
3 years ago
What is the mass number of an isotope with an atomic number of 57 and that has 69 neutrons?
Karolina [17]

Answer:

mass number=126

Explanation:

57+69=126

7 0
2 years ago
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