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vesna_86 [32]
3 years ago
5

Which material is LEAST dense? zircon oxygen carbon disulfide air

Physics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

Carbon disulfide soryy if im wrong\

Explanation:

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What do miles, kilometers, and light-years have in common?<br><br>​
Radda [10]

They are all units of measure of length

Explanation:

Length is a scalar quantity representing a distance between two points, and it can be expressed in different units.

The SI units of the length is the metre (m), which is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second.

A unit which is common used is a multiple of the meter, the kilometre (km) which corresponds to 1000 metres:

1 km = 1000 m

Another unit used in the UK system is the mile (mi), where the conversion factor between miles and metres is

1 mi = 1609.34 m

Finally, these units are not suitable to be used to measure astronomical distances - such as those between stars and galaxies. For this, another unit is used, which is the light-year (ly), which corresponds to the distance travelled by the light in a vacuum in one year, and its conversion factor to the metre is:

1 ly = 9.46\cdot 10^{15}ly

Learn more about distance here:

brainly.com/question/3969582

#LearnwithBrainly

6 0
3 years ago
who needs more friends on here go to my profile and hit thank you button and friend request and whoever do it first get brianlis
qwelly [4]

Answer:

BET SHORTY

Explanation:

THX

7 0
3 years ago
Read 2 more answers
The height of a typical playground slide is about 1.8 m and it rises at an angle of 30 ∘ above the horizontal.
Salsk061 [2.6K]

Answer:

5.94\ \text{m/s}

1.7

0.577

Explanation:

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

\theta = Angle of slope = 30^{\circ}

v = Velocity of child at the bottom of the slide

\mu_k = Coefficient of kinetic friction

\mu_s = Coefficient of static friction

h = Height of slope = 1.8 m

The energy balance of the system is given by

mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.8}\\\Rightarrow v=5.94\ \text{m/s}

The speed of the child at the bottom of the slide is 5.94\ \text{m/s}

Length of the slide is given by

l=h\sin\theta\\\Rightarrow l=1.8\sin30^{\circ}\\\Rightarrow l=0.9\ \text{m}

v=\dfrac{1}{2}\times5.94\\\Rightarrow v=2.97\ \text{m/s}

The force energy balance of the system is given by

mgh=\dfrac{1}{2}mv^2+\mu_kmg\cos\theta l\\\Rightarrow \mu_k=\dfrac{gh-\dfrac{1}{2}v^2}{gl\cos\theta}\\\Rightarrow \mu_k=\dfrac{9.81\times 1.8-\dfrac{1}{2}\times 2.97^2}{9.81\times 0.9\cos30^{\circ}}\\\Rightarrow \mu_k=1.73

The coefficient of kinetic friction is 1.7.

For static friction

\mu_s\geq\tan30^{\circ}\\\Rightarrow \mu_s\geq0.577

So, the minimum possible value for the coefficient of static friction is 0.577.

8 0
3 years ago
What would occur if there was a gain-of-function mutation in the promoter for the cyclin E gene such that cyclin E protein was a
rjkz [21]

Answer:

b) Cells will pass through the G1/S checkpoint even if conditions are not ideal for cell division.

Explanation:

In the given problem, if there exists a gain-of-function mutation for the given cell, there would not be the formation of cyclin E when there is the possibility of cells movement via the checkpoint of the G1/S, even when there are non-deal conditions for the division of cell. Thus, the correct option in the lists of options is the option b.

7 0
4 years ago
The water from a fire hose follows a path described by y equals 3.0 plus 0.8 x minus 0.40 x squared ​(units are in​ meters). If
ivanzaharov [21]

Explanation:

It is given that, the water from a fire hose follows a path described by equation :

y=3+0.8x-0.4x^2........(1)

The x component of constant velocity, v_x=5\ m/s

We need to find the resultant velocity at the point (2,3).

Let \dfrac{dx}{dt}=v_x and \dfrac{dy}{dt}=v_y

Differentiating equation (1) wrt t as,

\dfrac{dy}{dt}=0.8\times \dfrac{dx}{dt}-0.8x\times \dfrac{dx}{dt}

v_y=0.8\times v_x-0.8x\times v_x

v_y=0.8v_x(1-x)

When x = 2 and v_x=5\ m/s

So,

v_y=0.8\times 5\times (1-2)

v_y=-4\ m/s

Resultant velocity, v=\sqrt{v_x^2+v_y^2}

v=\sqrt{5^2+(-4)^2}

v = 6.4 m/s

So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.

8 0
3 years ago
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