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SOVA2 [1]
3 years ago
11

Please actually help me. Thank you!

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
6 0

Answer:

I say 20 is ur best option

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Unknown # 41
Semmy [17]
Answer: Potassium Iodide, KI

Explanation:

Flame test colors:

Li+ = Crimson Red
Na+ = Bright Orange-Yellow
K+ = Lilac

Addition of nitric acid and silver nitrate (HNO3 and AgNO3),

Cl- = White precipitate
Br- = Creamy precipitate
I- = Yellow Precipitate

Hope this helps, brainliest would be appreciated :)
3 0
3 years ago
The following data is given to find the formula of a Hydrate:
umka21 [38]

The masses can be found by substractions:

  • Mass of CaSO₄.H2O (hydrate):

16.05 g - 13.56 g = 2.49 g

  • Mass of CaSO₄ anhydrate:

15.07 g - 13.56 g = 1.51 g

  • The mass of water is equal to the difference between the mass of the hydrate and the mass of the anhydrate:

2.49 g - 1.51 g = 0.98 g

  • The percent of water is found by the formula:

massWater ÷ massHydrate * 100%

0.98 g ÷ 2.49 g * 100% = 39.36%

  • The mole of water is calculated using water's molecular weight (18g/mol):

0.98 g ÷ 18 g/mol = 0.054 mol water

  • A similar procedure is made for the mole of salt (CaSO₄ = 136.14 g/mol)

1.51 g ÷ 136.14 g/mol = 0.011 mol CaSO₄

  • The ratio of mole of water to mole of anhydrate is:

0.054 mol water / 0.011 mol CaSO₄ = 0.49

In other words the molecular formula for the hydrate salt is CaSO₄·0.5H₂O

3 0
3 years ago
Type the correct answer in the box.
tatiyna

the mass of  1  mole of phosphorus atoms is approximately  30 g

hope this helps :)

4 0
3 years ago
Read 2 more answers
What information is provided by absolute dating that cannot be provided by relative dating
kiruha [24]
Relative dating is the process of determining whether an object or event is older or younger than other objects or events. Absolute dating is d<span>etermining the age of an event or object in years. From absolute dating, the real age of the object is obtained which is not present for relative dating. Hope this helps.</span>
6 0
3 years ago
Read 2 more answers
How many grams of O2(g) are needed to completely burn 15.6 g of C3H8(g)?
alexdok [17]
15.6gC3H8*44.1gC3H8*32gO2=11.32
7 0
3 years ago
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