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D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 mL
Answer: Reducing agent in the given reaction is
.
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in
is +2 and
has 0 oxidation state.
In
oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is
.
Answer:
3.6 times 10^4
Explanation:
Scientific notation is between 1-9. So, we move 36000 to 4 decimal places. SO it would be 3.6 times 10^4. Scientific Notation always has the base of 10 . Enjoy :)
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?
Answer:
Octasulfur is just S8. Eight S atoms in
a sort of crown shape. Sulfur Dioxide is a gas, SO2. Does that help?
Explanation: