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2 years ago

5

A light bulb that has more current running through it will...

1 answer:

RoseWind [281]2 years ago

4 0

C
It does not affect the brightess of a lightbulb

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You make the following measurements of an object 42kg and 22m3 what would the objects density be

miv72 [106K]

The density of the object is approximately 1.91 kg per m³.

42 kg is a measure of mass, and 22 m³ is a measure of volume. Knowing this, you can use the relationship $density = mass / volume$ to solve for the object's density.

42 kg $\div$ 22 m³ $\approx$ 1.91 kg per m³.

4 0

2 years ago

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The altitude of a hang glider is increasing at a rate of 6.75 m/s. At the same time, the shadow of the glider moves along the gr

Rufina [12.5K]

Answer:

16.45 m/s

Explanation:

Let y be the vertical distance and x be the horizontal distance

We are given that

The altitude of hang glider increasing at the rate= $v_y=\frac{dy}{dt}==6.75m/s$

The shadow of the glider moves along the ground at speed= $v_x=\frac{dx}{dt}=15m/s$

We have to find the magnitude of glider's velocity.

We know that

Magnitude of velocity= $v=\sqrt{v^2_x+v^2_y}$

Substitute the values

$v=\sqrt{(15)^2+(6.75)^2}$

$v=\sqrt{225+45.5625}$

$v=16.45m/s$

Hence, the magnitude of glider's velocity=16.45 m/s

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2 years ago

You have created a document that uses the term Frank L. Wright over 30 times. You want to change every occurrence of this term t

fgiga [73]

Find and Replace dialog box is probably the most useful.

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3 years ago

Can Someone Please Help Me For 10 Points.

Natalija [7]

Answer: C

Explanation: The warm, wet air in a low pressure system has risen up and cooled down.

Please give Brainliest if you can!

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2 years ago

Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia

melisa1 [442]

Answer:

$H_2 = 91.55 km$

Explanation:

Gravity on the surface of planet is given as

$g = \frac{GM}{R^2}$

as we know that

$M = 8.93 \times 10^{22} kg$

$R = 1821 km$

now gravity on the planet is

$g = \frac{(6.67 \times 10^{-11})(8.93 \times 10^{22})}{(1821 \times 10^3)^}$

so we have

$g = 1.8 m/s^2$

now we know that

$H_{max} = \frac{v^2}{2g}$

so we will say

$\frac{H_1}{H_2} = \frac{g_2}{g_1}$

$\frac{500}{H_2} = \frac{9.81}{1.8}$

$H_2 = 91.55 km$

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2 years ago