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alina1380 [7]
3 years ago
9

If 18.0 g of CO2 is produced in the reaction of C2H2 with O2 to form CO2 and

Chemistry
1 answer:
Tanya [424]3 years ago
5 0

Answer:

3.68 g

Explanation:

n_{CO2} = 18 ÷ 44 = 0.4

2C2H2 + 5O2 → 4CO2 + 2H2O

   2       :    5      :    4      :    2  

                             0.409                 (moles)

⇒ n_{H2O} = 0.409 × 2 ÷ 4 = 0.2045 moles

⇒ m_{H2O} = 0.2045 × 18 = 3.68 grams

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A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )
Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

Explanation:

Number of moles of HCl present initially = \frac{0.1200}{1000}\times 50.0 moles = 0.00600 moles

Neutralization reaction (back titration): NaOH+HCl\rightarrow NaCl+H_{2}O

According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = \frac{0.0980}{1000}\times 23.60 moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

3 0
3 years ago
How many milliliters of C5H8 can be made from 366 mL C5H12 ?
zlopas [31]

The number of Ml  of C₅H₈  that can  be  made  from 366  ml  C₅H₁₂  is 314.7 ml  of C₅H₈


  <u><em>calculation</em></u>

 step  1: write  the  equation for  formation of C₅H₈

C₅H₁₂  →  C₅H₈  + 2 H₂

Step 2: find the mass of C₅H₁₂

mass = density × volume

= 0.620 g/ml × 366 ml =226.92 g

Step 3: find moles  Of  C₅H₁₂

moles  = mass÷  molar mass

from periodic table the  molar mass of  C₅H₁₂ = (12 x5) +(  1 x12) = 72 g/mol

moles = 226.92 g÷ 72 g/mol =3.152 moles

Step 4: use the  mole ratio  to determine the  moles of C₅H₈

C₅H₁₂:C₅H₈  is 1:1  from equation above

Therefore the  moles of C₅H₈  is also = 3.152  moles

Step 5: find the mass  of C₅H₈

mass = moles x molar mass

from periodic table the  molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol

= 3.152  moles x 68 g/mol = 214.34 g

Step 6: find Ml of  C₅H₈

=mass / density

= 214.34 g/0.681 g/ml = 314.7 ml



8 0
3 years ago
2zns(s)+3o2(g)—&gt;2zno(s)+2so2(g)
Paha777 [63]

This is an example of displacement reaction

<u>Explanation:</u>

  • The chemical reaction in which the one element replaces the other element in a compound is called a displacement reaction. This reaction is also called a replacement reaction.

                                AB + C -----> AC +B

                        2ZnS + 3O2 -----> 2ZnO + 2SO2

  • This happens when A is more reactive than B and gives a stable product. Here the zinc sulfide compound reacts with the oxygen element to the stable product of zinc oxide and sulfur dioxide.
  • In short, the more reactive element displaces the less reactive element is called a displacement reaction.
8 0
3 years ago
Compare and contrast epithelial and muscle.
jekas [21]

Answer:

Epithelial tissues act as coverings, controlling the movement of materials across their surface. Connective tissue binds the various parts of the body together, providing support and protection. Muscle tissue allows the body to move and nervous tissues functions in communication.

Explanation:

6 0
3 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb ( NO 3 ) 2
nikklg [1K]

Answer : The volume of NH_4I solution required is, 2.93 L

The number of moles of PbI_2 formed from the reaction is, 0.662 moles.

Explanation :

First we have to calculate the initial moles of Pb(NO_3)_2.

\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}

\text{Moles of }Pb(NO_3)_2=0.700M\times 0.945L=0.662mol

Now we have to calculate the moles of NH_4I

The balanced chemical reaction is:

Pb(NO_3)_2(aq)+2NH_4I(aq)\rightarrow PbI_2(s)+2NH_4NO_3(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react with 2 moles of NH_4I

So, 0.662 mole of Pb(NO_3)_2 react with 0.662\times 2=1.32 moles of NH_4I

Now we have to calculate the volume of NH_4I

\text{Volume of }NH_4I=\frac{\text{Moles of }NH_4I}{\text{Concentration of }NH_4I}

\text{Volume of }NH_4I=\frac{1.32mol}{0.450mol/L}=2.93L

Now we have to calculate the moles of PbI_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react to give 1 moles of PbI_2

So, 0.662 mole of Pb(NO_3)_2 react to give 0.662 moles of PbI_2

Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

7 0
3 years ago
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