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alina1380 [7]
3 years ago
9

If 18.0 g of CO2 is produced in the reaction of C2H2 with O2 to form CO2 and

Chemistry
1 answer:
Tanya [424]3 years ago
5 0

Answer:

3.68 g

Explanation:

n_{CO2} = 18 ÷ 44 = 0.4

2C2H2 + 5O2 → 4CO2 + 2H2O

   2       :    5      :    4      :    2  

                             0.409                 (moles)

⇒ n_{H2O} = 0.409 × 2 ÷ 4 = 0.2045 moles

⇒ m_{H2O} = 0.2045 × 18 = 3.68 grams

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Describe what happens when ice changes<br> into liquid water.
chubhunter [2.5K]

Answer:

When ice changes into liquid water it melts. The solidified ice in the frozen, would melt via the burning sun shooting its streaks down at the ice. Which causes the ice to melt, and turn into liquid water.

Explanation:

pp poopoo

3 0
3 years ago
Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 28.7 moles of FeO. Y
Alexxx [7]

Answer:

43.05 moles of Al needed to react with 28.7 moles of FeO.

Explanation:

Given data:

Moles of FeO = 28.7 mol

Moles of Al needed to react with FeO = ?

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Now we will compare the moles of Al with FeO.

                            FeO        :           Al

                             2            :            3

                          28.7          :         3/2×28.7 = 43.05 mol

Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.

8 0
3 years ago
Elle wanted to test how temperature affects the rate of evaporation. She had three setups:
Pie

Answer:

Temperature

Explanation:

Here the factor that Elle is controlling is the temperature. So temperature here is the independent variable and the dependent variable is the rate of evaporation of water.  Independent variable is controlled during the experiment setup and the outcome of the dependent variable depends on the independent variable.

5 0
3 years ago
A scientist prepared an aqueous solution of a 0.45 M weak acid. The pH of the solution was 2.72. What is the percentage ionizati
aleksandr82 [10.1K]

Answer:

0.42%

Explanation:

<em>∵ pH = - log[H⁺].</em>

2.72 = - log[H⁺]

∴ [H⁺] = 1.905 x 10⁻³.

<em>∵ [H⁺] = √Ka.C</em>

∴ [H⁺]² = Ka.C

∴ ka = [H⁺]²/C = (1.905 x 10⁻³)²/(0.45) = 8.068 x 10⁻⁶.

<em>∵ Ka = α²C.</em>

Where, α is the degree of dissociation.

<em>∴ α = √(Ka/C) </em>= √(8.065 x 10⁻⁶/0.45) = <em>4.234 x 10⁻³.</em>

<em>∴ percentage ionization of the acid = α x 100</em> = (4.233 x 10⁻³)(100) = <em>0.4233% ≅ 0.42%.</em>

4 0
3 years ago
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Describe how to draw a 3-heptyne
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You can't really describe it but this is what it looks like http://www.chemspider.com/Chemical-Structure.453291.html
3 0
3 years ago
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