➢225 mL of solution containing<span> 0.486 </span>mole<span> of solute </span>mol<span> HCl. Use </span>molarity<span> as a conversion factor.</span>Mol<span> HCl = 2.5 L soln x 0.10 </span>mol<span> HCl by diluting 25.0 mL of 6.00 M HCl to a </span>total volume<span> of 50.0 Note: Vc and Vd do not </span>have<span> to be ➢The mass of MgCl2 in a </span>2.75 mole<span> sample 3.447 g of </span>CO2<span> and 1.647 g of H2O.</span>
Answer : The time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.
Explanation :
Half-life = 29.8 s
First we have to calculate the rate constant, we use the formula :



Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:

where,
k = rate constant = 
t = time passed by the sample = ?
a = let initial amount of the reactant = x M
a - x = amount left after decay process = 
Now put all the given values in above equation, we get


Therefore, the time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.
Answer:
1. Interpret Laws
3. Federal? I think...
5. Appointed by the president
6. Judicial review
8. Civil
9. Judicial review
11. The constitution does not allow it
Explanation:
The electronegativity of the element affects the ability of its compounds to dissolve in different solvents.
<h3>What is the meaning of electronegativity?</h3>
Electronegativity is a measure of an atom's ability to attract shared electrons to itself.
Polar bonds have a positive and negative side to them, and therefore can attract water dipoles and dissolve in water.
If the polarities of the solvent and solute match (both are polar or both are nonpolar), then the solute will probably dissolve.
If the polarities of the solvent and solute are different (one is polar, one is nonpolar), the solute probably won't dissolve.
Hence, option D is correct.
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B.consumers becuse all anmails are consumers....................................................................................................................................................................................................................................................................................................................................