Answer:
Explanation:
It is a case of adiabatic expansion .
T₁ , T₂ are initial and final temperature , V₁ and V₂ are initial and final volume.
Given ,
V₂ = 3 V₁ and T₁ = 292 . γ for air is 1.4 .
1.552 = 292 / T₂
T₂ = 188 K .
The velocity of the air relative to the ground is
The velocity of the plane relative to the air is
where is the direction the plane needs to point so that the resultant vector - the velocity of the plane relative to the ground - is
Here is the speed of the plane relative to the ground.
So we have
Use a calculator to solve for and ; you should find
Answer: i'm not an expert in this field but i would describe a dwarf planet as a "planet not in the big leagues"
Answer:
1000
Explanation:
the formula of time taken= d/s. t=15000÷15 t=1000. I hope it helps
Answer:
(a) v = 5.42m/s
(b) vo = 4.64m/s
(c) a = 2874.28m/s^2
(d) Δy = 5.11*10^-3m
Explanation:
(a) The velocity of the ball before it hits the floor is given by:
(1)
g: gravitational acceleration = 9.8m/s^2
h: height where the ball falls down = 1.50m
The speed of the ball is 5.42m/s
(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.
You use the following formula:
(2)
vo: velocity of the ball where it starts its motion upward
You solve for vo and replace the values of the parameters:
The velocity of the ball is 4.64m/s
(c) The acceleration is given by:
The acceleration of the ball is 2874.28/s^2
(d) The compression of the ball is:
THe compression of the ball when it strikes the floor is 5.11*10^-3m