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3 years ago

The graph shows the amplitude of a passing wave over time in seconds (s).

Physics

2 answers:

FinnZ [79.3K]3 years ago

5 0

Answer:

Option B. 0.3 Hz

Explanation:

From the question given above, the following data were obtained:

Period (T) = 3 s

Frequency (f) =?

Frequency is related to the period according to the following equation:

Frequency (f) = 1 / period (T)

f = 1/T

With the above formula, we can obtain the frequency wave as illustrated below:

Period (T) = 3 s

Frequency (f) =?

f = 1/T

f = 1/3

f = 0.3 Hz

Therefore, the frequency of the wave is 0.3 Hz

Gelneren [198K]3 years ago

5 0

Answer:

The answer is 0.3 Hz

Explanation:

I took AP EX quiz.

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If an object on Earth weighs 100N what is its weight in pounds?

oksian1 [2.3K]

Answer:

10.2 lbs

Explanation:

m=F/g

m=100N/9.8

m=10.2040816 lbs

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3 years ago

Which of these galaxies is most likely to be oldest?

ycow [4]

Answer:

a galaxy observed at a distance of 5 billion light-years

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2 years ago

An enormous thunderstorm covers Dallas-Ft. Worth. Your best friend Clark is a storm chaser and heads to the center of the storm

Rus_ich [418]

Answer:

t = 0.437 s

Explanation:

The speed of sound is a constant that is worth v = 343 m / s

v = d / t

t = d / v

the time it takes for the sound to reach Clark at d = 150 m is

t = 150/343

t = 0.437 s

This same sound takes much longer to reach you

t₂ = 127 10³/343

t₂ = 370 s

6 0

3 years ago

Superman stops a "speeding locomotive" of mass 8.0x103 kg in 4.0 seconds. If the train was originally moving at 40.m/s,

madreJ [45]

Hello!

a) What is the change in momentum?

The change of the momentum is the velocity, because the velocity is reduced to zero.

We can calculate the aceleration, applicating the formula:

$\boxed{a=\frac{V-Vi}{t} }$

Like you see, the final velocity will be zero, so:

$a = \dfrac{0m/s-40m/s}{4s}$

$a = \dfrac{-40m/s}{4s}$

$a = -10\ m/s^{2}$

Like you see, the aceleration applicate by superman is of -10 m/s^2.

If the aceleration is negattive, means the velocity will decrease.

b.) What is the magnitud of the force wich superman exerts on the train?

For calculate the force applicate for superman, lets applicate the second law of Newton:

$\boxed{F=ma}$

Lets replace and resolve it:

F = 8x10^3 kg * (-10 m/s^2)

F = 8000 kg * (-10 m/s^2)

F = -80 000 N

The force applicated is of -80000 Newtons.

When the force is negative means the force applicated in the another direction of the object what is traveling.

8 0

3 years ago

During a very quick stop, a car decelerates at 6.8 m/s^2. Assume the forward motion of the car corresponds to a positive directi

geniusboy [140]

Answer:

-24.28571 rad/s²

29.57239 revolutions

3.91176 seconds

52.026478 m

Explanation:

$a_t$ = Tangential acceleration = -6.8 m/s²

r = Radius of wheel = 0.28

$\omega_i$ = Initial angular velocity = 95 rad/s

$\theta$ = Angle of rotation

$\omega_f$ = Final angular velocity

t = Time taken

Angular acceleration is given by

$\alpha=\frac{a_t}{t}\\\Rightarrow \alpha=\frac{-6.8}{0.28}\\\Rightarrow \alpha=-24.28571\ rad/s^2$

The angular acceleration is -24.28571 rad/s²

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-95^2}{2\times -24.28571}\\\Rightarrow \theta=185.80885\ rad=185.80885\times \frac{1}{2\pi}\\\Rightarrow \theta=29.57239\ rev$

The number of revolutions is 29.57239

$\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{0-95}{-24.28571}\\\Rightarrow t=3.91176\ s$

The time it takes for the car to stop is 3.91176 seconds

Linear distance

$s=r\theta\\\Rightarrow s=0.28\times 185.80885\\\Rightarrow s=52.026478\ m$

The distance the car travels is 52.026478 m

8 0

3 years ago