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m_a_m_a [10]
3 years ago
12

A converging lens can be defined as __________

Physics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

a lens that causes parallel light rays to separate from each other

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A less-dense liquid of density rho1 floats on top of a more-dense liquid of density rho2. A uniform cylinder of length l and den
Umnica [9.8K]

Answer:

Explanation:

Given

\rho=density\ of\ cylinder\\\rho_1=less\ dense\ cylinder\\\rho_2=more\ dense\ cylinder

Suppose V is the volume of a cylinder

Also L_1=length\ in\ less\ dense\ part\\L_2=length\ in\ dense\ part\\L=length\ of\ cylinder\\V=A\times L\\where\ A=area\ of\ cross-section\\

Now, we can write

The weight of the cylinder is supported by the buoyant forces of two liquids

\rho Vg=\rho_1 V_1g+\rho_2 V_2g\\\rho ALg=\rho_1 A\times L_1g+\rho_2 A\times L_2g\\\\\rho L=\rho_1 L_1+\rho_2 L_2\\Also, L=L_1+L_2

using the above equation we can write

L_2=\frac{\rho-\rho_1}{\rho_2-\rho_1}\cdot L\\\frac{L_2}{L}=\frac{\rho-\rho_1}{\rho_2-\rho_1}

5 0
3 years ago
A mass on a string of unknown length oscillates as a pendulum with a period of 1.8 s. What is the period in the following situat
Maslowich

Answer:

Using

Period ( P) is given as

P~√(L/g).

a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds

b) using the formula above ,period varies with the square root of the length. Thus , when the length doubles, the period is multiplied by √2. So, the period is 1.8s*√2 = 2.54s

c) in this case, the period is multiplied by √(1/2).

1.8√(1/2)=1.27s.

d) amplitude of the pendulum doesn't affect the period (unless itsvery high, so, the period is still 1.8s

7 0
4 years ago
Use the drop-down menu to answer the question. which sound wave-object interaction is used by animals in echolocation?
Dima020 [189]

Answer:

Reflection

Explanation:

6 0
3 years ago
A road perpendicular to a highway leads to a farmhouse located 55 mile away. an automobile traveling on the highway passes throu
saveliy_v [14]

The answer in this question is 44.7533 mphGiven information which we denote I as the distance of the automobile between the farmhouse, and S = the distance past the intersection of the highway and the road. 
Then I^2 = 5^2 + s^2. Taking the derivative of both sides of this equation yields 2I(ds/dt) = 2s(ds/dt), so (dl/dt) = s(ds)/I(dt). When the automobile is 7 miles past the intersection we have;dl/dt = 55√(7/5^2 +7^2) and gives us the answer of approximately 44.7533 mph
3 0
4 years ago
A ball is dropped from the top of a 77 m building. With what speed does the ball hit the ground? _________ m/s
vitfil [10]

Answer:

38.87 m/s

Explanation:

Given that the ball is dropped from a height = 77 m

u = 0 m/s

s = 77 m

a = g = 9.81 m/s²

Applying the expression as:

v^2-u^2=2as

Applying values as:

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 77+0^2}\\\Rightarrow v=38.87\ m/s

<u>The speed with which the ball hit the ground = 38.87 m/s</u>

3 0
3 years ago
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