Lower flammable limit means the lowest concentration of a material that will propagate a flame.
What is hazardous atmosphere?
It is an atmosphere that may expose employees to risk of death, incapacitation, impairment of ability to self-rescue, injury, or acute illness from one or more of following causes
- Flammable gas, vapor, or mist in excess of 10 percent of lower flammable limit (LFL)
- Airborne combustible dust at concentration that meets or exceeds its LFL
What is lower flammable limit?
- It means the lowest concentration of a material that will propagate a flame.
- The LFL is usually expressed as percent by volume of material in air (or other oxidant)
- Atmospheres with concentration of flammable vapors at or above 10 percent of lower explosive limit (LEL) are considered hazardous when located in confined spaces.
- However, atmospheres with flammable vapors below 10 percent of LEL are not necessarily safe. Such atmospheres are too lean to burn
Learn more about lower flammable limit at brainly.com/question/2456135
#SPJ4
<h3>
Answer:</h3>
2.572 g
<h3>
Explanation:</h3>
From the question;
Volume of Helium gas, V is 18.5 L
Pressure,P is 85.5 kPa
Temperature, T is 296 K
We are required to calculate the mass of Helium gas
<h3>Step 1: Calculate the number of moles of Helium gas </h3>
- This can be done using the ideal gas equation.
- The ideal gas equation is PV=nRT, where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant which is 8.314 kPa.L/K.mol
Rearranging the formula;
Thus,
n = 0.643 moles
Therefore, moles of Helium are 0.643 moles
<h3>Step 2: Calculate the mass of Helium gas </h3>
To calculate the mass we multiply the number of moles by the molar mass.
Mass = Number of moles × Molar mass
Molar mass of Helium = 4.00 g/mol
Therefore;
Mass of He = 0.643 moles × 4.00 g/mol
= 2.572 g
Hence, mass of helium gas is 2.572 g
Answer:
See answer and picture below
Explanation:
In this case, the key to get an idea of how is the starting ether is with the final product and the empirical formula of the ether.
First, the empirical formula of the ether gives us information of the structure of the ether. This ether could be either an alkene, alkane or cycloalkane.
Alkane cannot be because alkane's formula is CnH(2n+2), so it's either an alkene or cycloalcane (CnH2n).
However, as we can see, it reacts with HI in excess, so, it cannot be an alkene because in this case the acid will react with the double bond of the ether too forming another product. This discart the fact that the ether has a double bond. So it has to be a cycloalkane.
As the innitial structure it's an ether, it should be either a cyclohexane or cyclopentane with a methyl group attached. So, how can we know which of these structures is? well, we can actually do the reaction with both reactants and see which match. In the attached picture you have the answer.
Hope this helps.
Answer: Look it up on the internet
Explanation: hi just wanted to tell you youre amazing
Answer:
stars
earth isn't made of gas. (and you can always see it)
moon us not gas, or give off heat
sun is only visible during the day