To solve this problem we will start from the given concept in which the number of turns is equivalent to the length of the thread per circumference of spool. That is:
Where,
l = length of the thread
= circumference of spool
For \phi we have that,
For l we have that
l = 62.8m
Finally the number of Turns would be,
Therefore the number of turns of thread on the spool are 1000turns.
There isnt enough information to answer the question, the missing variable is "distance from said falling spot and ground"
Answer:
the mass of the truck is 2 kg.
Explanation:
Given;
mass of the car, m₁ = 3 kg
initial velocity of the car, u₁ = 40 m/s
initial velocity of the truck, u₂ = 60 m/s
let the mass of the truck = m₂
Apply the principle of conservation of linear momemtum;
m₁u₁ = m₂u₂
m₂ = (m₁u₁) / u₂
m₂ = (3 x 40) / (60)
m₂ = 2 kg
Therefore, the mass of the truck is 2 kg.
Answer:
966.22 mph
Explanation:
Velocity of plane with respect to wind (Vp,w)= 612 mph east
velocity of wind with respect to ground, (Vw,g) = 362 mph at 15° North of
east
Write the velocities in vector form
Use the formula for the relative velocity
Where, V(p,w) is the velocity of plane with respect to wind
V(p,g) is the velocity of plane with respect to ground
V(w,g) is the velocity of wind with respect to ground
So,
Magnitude of velocity of lane with respect to ground
V(p,g) = 966.22 mph