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a_sh-v [17]
3 years ago
10

A 125-g coin is placed 8.0 cm from the axis of rotation of a horizontally rotating turntable as shown. The coefficient of static

friction between the coin and the turntable is μs . The turntable makes exactly 1.0 revolution per second and the coin remains in place without slipping. [a] (8 pts) Draw a free-body force diagram for the coin. [b] (10pts)What is the frictional force acting on the coin? [c] (12pts)When the rotational speed is increased to 1.2 revolutions per second, the coin starts to slip. Calculate the coefficient of static friction μs between the coin and the turntable?
Physics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

zhvshshisvdiscdoscd if vdidg

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Alex Ar [27]

1 Kg = 1,000g

Therefore 1.33 × 10^-7 g = 1.33 × 10^-10 kg

1m³ = 1,000,000cm³

Therefore 1 cm³ = 1 × 10^-6 m³

Dividing the mass per unit volume you get:

(1.33 × 10^-10 kg) ÷ (1 × 10^-6 m³)

= 1.33 × 10^(-10--6) = 1.33 × 10^(-10 + 6) = 1.33 × 10^-4 kg/m³

Density = 1.33 × 10^-4 kg/m³

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Which of the following has the greatest inertia? A. a toy car . . B. a jet airliner . . C. a full-size car . . D. a pick-up truc
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Inertia is defined as the property of matter by which causes it to resist changes in its state of motion such as changes in velocity. From the given options above, the option that has the greatest inertia would be option B. A jet airliner. 
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What is the rate of vibration measured in
jek_recluse [69]

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I'm not 100% sure tbh but the only thing I think makes sense to represent vibration would be frequency which is measure in Hertz (Hz)

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Read 2 more answers
A 70.0-kg ice hockey goalie, originally at rest, catches a 0.150-kg hockey puck slapped at him at a velocity of 35.0 m/s. Suppos
brilliants [131]

Answer:

v₂=- 34 .85 m/s

v₁=0.14 m/s

Explanation:

Given that

m₁=70 kg ,u₁=0 m/s

m₂=0.15 kg ,u₂=35 m/s

Given that collision is elastic .We know that for elastic  collision

Lets take their final speed is v₁ and v₂

From momentum conservation

m₁u₁+m₂u₂=m₁v₁+m₂v₂

70 x 0+ 0.15 x 35 = 70 x v₁ + 0.15 x v₂

70 x v₁ + 0.15 x v₂=5.25                   --------1

v₂-v₁=u₁-u₂            ( e= 1)

v₂-v₁ = -35        --------2

By solving above equations

v₂=- 34 .85 m/s

v₁=0.14 m/s

4 0
3 years ago
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