As per FBD while its accelerating upwards
we can say that
here normal force is given as
now mass is given as
now we will have
Now while accelerating downwards we can say by FBD
again plug in all values
Given Information:
slope angle = θ = 30°
spring constant = k = 30 N/m
compressed length = x = 10 cm = 0.10 m
mass of ice cube = m = 63 g = 0.063 kg
Required Information:
distance traveled by ice cube = d = ?
Answer:
distance traveled by ice cube = 0.48 m
Explanation:
Using the the principle of conversation of energy, the following relation holds true for this case,
mgh = 1/2*kx²
h = 1/2*kx²/mg
Where h is the height of the slope, m is the mass of ice cube, k is the spring constant and x is the compressed length o the spring and g is gravitational acceleration.
h = 1/2*kx²/mg
h = 1/2*30(0.1)²/0.063*9.8
h = 0.242 m
From trigonometry ratio,
sinθ = h/d
d = h/sinθ
d = 0.242/sin(30)
d = 0.48 m
Therefore, when the ice cube is released, it will travel a total distance 0.48 up the slope before reversing direction.
E=kq/r^2
q=(E*r^2)/k
q=(.086N/C)(1.7m^2)/(8.99*10^9N*m^2/C^2)
q=2.76*10^-11 C
q=2.8*10^-11 C
Answer:
b
Explanation:
it compresses hot air turning into cool air almost like a reverse tornado
