True
The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.
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Answer:
<em>The direction of the magnetic field on point P, equidistant from both wires, and having equal magnitude of current flowing through them will be pointed perpendicularly away from the direction of the wires.</em>
Explanation:
Using the right hand grip, the direction of the magnet field on the wire M is counterclockwise, and the direction of the magnetic field on wire N is clockwise. Using this ideas, we can see that the magnetic flux of both field due to the currents of the same magnitude through both wires, acting on a particle P equidistant from both wires will act in a direction perpendicularly away from both wires.
The lowest energy of electron in an infinite well is 1.2*10^-33J.
To find the answer, we have to know more about the infinite well.
<h3>What is the lowest energy of electron in an infinite well?</h3>
- It is given that, the infinite well having a width of 0.050 mm.
- We have the expression for energy of electron in an infinite well as,
- Thus, the lowest energy of electron in an infinite well is,
Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.
Learn more about the infinite well here:
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Answer:
Bar graph
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Line Graph
Explanation:
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