Answer:
65.73N
Explanation:
The frictional force is a force that opposes the motion of an object on a flat surface or an inclined surface.
It is always acting up an incline plane .
Since the pipe will tend to roll up the plane, then both the impending force P also known as frictional force and the moving force Fm both will be acting up the plane.
The net force acting up the plane is
Fnet = P + Fm... (1)
The force perpendicular to the plane known as the normal reaction R must be equal to the force acting along the ramp in other to keep the body in equilibrium i.e R = Fnet
If R = W = mgcos (theta)
and Fm = mgsin(theta)
Then mgcos theta = Fnet
mgcos (theta) = P+Fm
mgcos (theta) = P+mgsin(theta)
P = mgcos (theta) - mgsin(theta)... (2)
Given mass = 10kg
g = 9.81m/s
We can get theta from the formula;
µ = Ff/R = wsin theta/wcos theta
µ = sin theta/cos theta
µ = tan(theta)
0.3 = tan (theta)
theta = arctan0.3
theta = 16.7°
P = 10(9.81)cos16.7° - 10(9.81)sin16.7°
P = 98.1(cos16.7°-sin16.7°)
P = 98.1(0.67)
P = 65.73N
The minimum force P required to cause impending motion is 65.73N
You’re right, bc I’m the question it says the pulley is at equilibrium
Answer:
Gravitational force is the force that attracts objects towards each other. Two factors that affect the gravitational force between objects are the mass of the two objects and the distance between
Explanation:
Gravity is what pulls us towards the Earth if we were to jump into the air, so it is the force that pulls things towards other things. The bigger the objects are the more gravity they have, so a planet has more gravity than say, an apple. Distance between objects also makes their gravity change, so the Earth's pull on the moon is different than the Earth's pull on the sun.
Hopefully this helps- let me know if you have any questions!
It would be a <span>electromagnetic wave
Hope that this would help you! =)</span>
The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.
<h3>What is work done?</h3>
Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.
From the Newton's law of motion,
ma =F-mg sinθ =0
So, the force F = mg sinθ
Plug the values, we get
F = 620N x sin 23.5°
F = 247.224 N
Work done by motor is W= F x d
The force is equal to the weight F = mg
So, W = 247.224 x 14.1
W = 3.486 kJ
Thus, the work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.
Learn more about Work done
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