T<u>he statement which fairly compares segment 2 and segment 3 </u>is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Since segment 2 starts at t = 60 s and ends at t = 150 s, the time interval is Δt = 150 - 60 = 90 s.
Also, segment 3 starts at t = 150 s and ends at t = 240 s, the time interval is Δt = 240 - 150 = 90 s.
So, their time periods are the equal.
We notice that segment 2 is less steep than segment 3 this implies that the acceleration in each segment is different, since the acceleration is the slope of the graph.
Since force is determined by acceleration, this implies that the force on segment 2 is different form the force acting in segment 3.
So, we have equal time periods but different forces.
So, <u>the statement which fairly compares segment 2 and segment 3 </u>is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Learn more about velocity-time graph here:
brainly.com/question/24788847
Density d=m/V
mass m=d.V=13.5×5=67.5g
m=67.5g
hope this helps you
Answer:
v₀ₓ = 28.6 m / s
Explanation:
This is a missile throwing exercise
y = 
t - ½ g t²
as the dart is thrown horizontally the vertical velocity is zero (I go = 0)
y = - ½ g t²
t = 
let's calculate
t = 
t = 0.175 s
the expression for horizontal displacement is
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 5.00 / 0.175
v₀ₓ = 28.6 m / s
Because: Some of the work done by the machine is used to overcome the friction created by the use of the machine. ... Work output can never be greater than work input. Machines allow force to be applied over a greater distance, which means that less force will be needed for the same amount of work.
