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frosja888 [35]
3 years ago
7

A toy car is given an initial velocity of 0.0 m/s and experiences a constant acceleration of 2.0 m/s2. What is the final velocit

y after 12.0 s?​
Physics
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

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A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per min
Harman [31]

Answer:

1.302\ \text{kg/s}

Explanation:

\rho = Density of water = 1\ \text{kg/L}

dV = Change in volume = 220\times 0.355\ \text{L}

dt = Time elapsed = 1 minute = 60 seconds

Mass flow rate is given by

\dot{m}=\rho\dfrac{dV}{dt}\\ =1\times \dfrac{220\times 0.355}{60}\\ =1.302\ \text{kg/s}

The mass flow rate is 1.302\ \text{kg/s}.

4 0
3 years ago
One student runs with a velocity of +10 m/s while a second student runs with a velocity of –10 m/s. Which student has the faster
larisa86 [58]

Answer:

The one with the faster velocity is the one with a velocity of -10m/s

7 0
3 years ago
A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.
Len [333]

Explanation:

Given

Velocity v = 23.0m/s

Distance S = 3.45m

Required

Time it will take the skier to reach the ground;

Using the equation of motion;

S = ut + 1/2gt²

3.45 = 23t + 1/2(9.8)t²

3.45 = 23t + 4.9t²

4.9t²+23t-3.45 = 0

Factorize;

t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)

t = -23 ±√529+67.62/9.8

t = -23±√596.62/9.8

t = -23±24.43/9.8

t = 1.43/9.8

t = 0.146 secs

Hence take the skier 0.146 secs to reach the ground.

b) Horizontal distance covered is the range;

Range = U√2H/g

Range = 23√2(3.45)/9.8

Range = 23√6.9/9.8

Range = 23√0.7041

Range = 23(0.8391)

Range = 19.29m

Hence the horizontal distance travelled in air is 19.29m

7 0
3 years ago
Does sound travel outside earth's atmosphere in space explain
Yuliya22 [10]
On a large scale, no. Sound travels through space by the compression and relaxation of molecules. When you speak to someone on Earth, each inflection of voice compresses local molecules, and relaxes the molecules around the compressed ones. In space, however, the large lack of molecules means that the compression waves can’t be transmitted from the sound to the listener.
8 0
3 years ago
A wooden cylinder of length L and cross-sectional area A is partially submerged in a liquid with the axis of the cylinder orient
SCORPION-xisa [38]

Answer:

F=\rho_LAdg

Explanation:

The buoyant force F is equal to the weight of the displaced fluid. The weight of the displaced fluid is W=m_dg, where m_d is the mass of the displaced fluid. The mass of the displaced fluid is m_d=\rho_LV_d, where \rho_L is the density of the fluid and V_d is the displaced volume, which is equal to the submerged volume of the cilinder V_d=V_s=Ad.

Putting all together we have:

F=W=m_dg=\rho_LV_dg=\rho_LAdg

7 0
3 years ago
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