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3 years ago

Please help, I really need this. Thanks

Physics

1 answer:

mariarad [96]3 years ago

3 0

Answer

Delta Q = change in thermal energy = c M * change in temperature

change in temperature = Q / (c * M)

change in temperature = -12 J / (390 J / Kg*deg * .012 kg

change in temp = -12 / (390 * .012) = - 2.56 deg C

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Answer:

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3 years ago

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Explanation:

Terminal velocity is given by:

$v_t=\sqrt{\frac{2mg}{\rho C_dA}}$

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$A=\frac{A_s}{2}=\frac{930cm^2}{2}=465cm^2\\465cm^2*\frac{1m^2}{10^4cm^2}=0.0465m^2\\560g*\frac{1kg}{10^3g}=0.56kg$

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3 years ago

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3 years ago

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vesna_86 [32]

Answer:

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