Question

If you have 25.0 ml of a 6.50m naoh solution and you add 10.0 ml of water to it, what is the new concentration?

Answer 1

36.5ml is the new concentration so, its a chemical change if there's something new

Answer 2

Explanation:

The given data is as follows.

        $V_{1}$ = 25.0 ml,      $V_{2}$ = (10.0 ml + 25.0 ml) = 35.0 ml

        $M_{1}$ = 6.50 M,      $M_{2}$  

Relation between volume and molarity of the two liquids is as follows.

       $M_{1} \times V_{1}$ = $M_{2} \times V_{2}$

        $6.50 M \times 25.0 ml$ = $M_{2} \times 35.0 M$    

             $M_{2}$ = 4.64 M

Thus, we can conclude that new concentration is 4.64 M.