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Lisa [10]
3 years ago
6

Explain why it is not advisable to add water to acid when mixing them​

Chemistry
2 answers:
lilavasa [31]3 years ago
7 0

Answer:

Heat is released when strong acids are mixed with water. If you add water to acid, you form an extremely concentrated solution of acid initially and the solution may boil very violently, splashing concentrated acid.

Explanation:

hope that helps! :)

Damm [24]3 years ago
4 0

Answer:

<u><em>Consequence</em></u>

  1. you form an extremely concentrated solution of acid initially.
  2. and the solution may boil very violently, splashing concentrated acid.  
<h2>I hope this helped! :)</h2>

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Which factor below does not affect how fast a solute dissolves in a solvent?
Anit [1.1K]
Stirring this is because the three elements are factors affecting dissolving of a solvent. Eg temprature affects in hotness or coldness, Particle size affects whether it is big or small while quantity of soluble affects by the amount
3 0
3 years ago
Read 2 more answers
BRAINLIESTTT ASAP!!! PLEASE HELP ME :))
lys-0071 [83]

Answer:

Multiply 1.25 by 0.04 and divide the result obtained by 1,000

Explanation:

Since there is .04 oz in 1 gram, we take the 1.25 gram and multiply by .04.

Next, to convert per liter to per milliliter, we divide by 1,000.

3 0
3 years ago
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
3 years ago
Karla added green pellets to a container of water before she began watering her lawn. What correctly describes
kvv77 [185]

The correct answer is C. The water is the solvent because the green pellets dissolved in it.

Explanation:

In solutions, the are two substances involved, the solvent and the solute. The solvent is usually a liquid substance; additionally, the solvent dissolves another substance, which is known as the solute. For example, if you dissolve a spoon of salt in a glass of water, the solute is the salt which is the substance dissolved and the solvent is the water because the solute is dissolved in it. According to this, in the case presented the water is the solvent because the green pellets which are the solute dissolve in it.

5 0
3 years ago
Calculate the mass percent by volume of 330.1 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.
nadezda [96]

Answer: The mass percent by volume is 101.6%

Explanation:

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

mass percent by volume =\frac{\text {mass of solute}\times 100}{\text {Volume of solution in ml}}\%

Given : mass of glucose = 330.1 g

volume of solution = 325 ml

Thus mass percent by volume =\frac{330.1g\times 100}{325ml}=101.6\%

Thus the mass percent by volume is 101.6%

3 0
3 years ago
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