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2 years ago

6

A deer is walking at 2.27speeds up to 13.42 m/s, covering a distance of 53.2 meters during this acceleration. How much time did

it take him to do this.

1 answer:

lakkis [162]2 years ago

6 0

Answer:

t=3.964s

Explanation:

Use t=d/s

t=53.2m/13.42m/s= 3.964s

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A particular baseball pitcher throws a baseball at a speed of 39.1 m/s (about 87.5 mi/hr) toward home plate. We use g = 9.8 m/s2

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There is no acceleration in the horizontal direction (just g in the vertical), so we can use v = d/t, where v is velocity, d is distance and t is time. We can solve for time like so: t = d/v, we can plug in numbers (v is 39.1m/s completely in the horizontal direction, so no need to break it down with sin's and cos's, just plug it in) and we get t = (16.6m)/(39.1 m/s) = 0.42 s. Keep in mind it wouldn't fall far enough vertically to hit home plate (though we don't know the ball's initial height anyway), but would be in the air just above it. Cheers!

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