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3 years ago

What is 797 mm hg to atm?

Chemistry

2 answers:

VashaNatasha [74]3 years ago

5 0

Answer:

1.04868 Standard atmosphere

Aleksandr [31]3 years ago

4 0

Answer:

797 mm hg = 1.04868 atm

Explanation:

1 atm = 760 mm hg

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How many atoms are in 9.3moles of lithium?

vladimir1956 [14]

Answer:

3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms .

Explanation:

The relationship between atoms and moles is:

1 mole atoms =

6.022 × 10 (to the power of)23

atoms

In order to determine how many atoms occupy a given number of moles, multiply the given moles by

6.022 × 10 (to the power of)23

atoms/mole

In the case of 3.45 moles lithium (Li):

3.45 mol Li × 6.022 × 10 (to the power of)23 atoms Li/ 1 mol Li =

2.08 × 10 (to the power of)24

atoms Li rounded to three

3 0

3 years ago

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The process by which hot and cold air are transferred in the atmosphere is what

xz_007 [3.2K]

t can be transferred from one region to the other. In solids heat is transferred by a process called conduction. In vacuum heat transfer is by a process called radiation. In fluids (gases and liquids) heat is transferred by a process known as convection.

7 0

3 years ago

Combustion analysis of 0.600 g of an unknown compound containing carbon, hydrogen, and oxygen produced 1.043 g of CO2 and 0.5670

Aliun [14]

Answer : The empirical formula of the compound is $C_3H_8O_2$

Explanation :

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=1.043g$

Mass of $H_2O=0.5670g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 1.043 g of carbon dioxide, $\frac{12}{44}\times 1.043=0.284g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.5670 g of water, $\frac{2}{18}\times 0.5670=0.063g$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.600) - (0.284 + 0.063) = 0.253 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.284g}{12g/mole}=0.0237moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.063g}{1g/mole}=0.063moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.253g}{16g/mole}=0.0158moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0158 moles.

For Carbon = $\frac{0.0237}{0.0158}=1.5$

For Hydrogen = $\frac{0.063}{0.0158}=3.98\approx 4$

For Oxygen = $\frac{0.0158}{0.0158}=1$

The ratio of C : H : O = 1.5 : 4 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 3 : 8 : 2

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 8 : 2

Hence, the empirical formula for the given compound is $C_3H_8O_2$

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3 years ago

Situation- I took time away from preparing for my Quiz competition to help two of my neighbourhood friends for their class exam.

blsea [12.9K]

Sorry I did not understand the question

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3 years ago

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How are the circulatory systems in animals and plants alike

yKpoI14uk [10]

Ok, so the circulatory system in plants and animals is like a method of transport. Both plants and animals use this to transport waste and nutrition.

-Agarvated

(hope this helps, have a great day!)

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3 years ago