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3 years ago

Elements with the same number of electron shells are in the same

Chemistry

1 answer:

Anarel [89]3 years ago

3 0

Answer:

Elements with the same number of electrons in their outermost shell show similar chemical properties. Example 1: Fluorine, chlorine, bromine, and iodine each have 7 electrons in their outermost shell. These so-called halogens are also quite similar in their chemical behavior.

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Formula equation is more informative than a word equation why

Taya2010 [7]

Answer:

yes

Explanation:

this is because the formula equation shows the details on how they solved the equation

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3 years ago

State the Constituents of the following alloys:magnalium and bronze

____ [38]

Magnalium: Magnesium and Aluminum

Bronze: Copper, Tin, Arsenic, Phosphorus, Aluminum, Manganese and Silicon (whichever you learned in class from those)

8 0

3 years ago

Identify the products of this single-replacement reaction between sulfuric acid and aluminum. Then balance the equation. (2 poin

jeka94

The products of this reaction between aluminum and sulfuric acid are two: hydrogen and aluminum sulfate.

<h3>What are the products in a reaction?</h3>

This concept refers to the substances obtained at the end of the reaction.

<h3>What does it mean to balance an equation?</h3>

It means to make sure there are the same molecules in the reactants and products.

<h3>What are the products in this reaction?</h3>

Al + H2SO4 = Al2 (SO4)3 + H2
Al2 (SO4)3 = Aluminium sulfate
H = Hydrogen

<h3>What is the balanced equation?</h3>

2Al + 3H2SO4 = Al2 (SO4)3 + 3H2

Learn more about chemical reaction in: brainly.com/question/3461108

7 0

2 years ago

The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga

Rashid [163]

Answer:

Final temperature of the gas is 576 $^{0}\textrm{C}$ .

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

where $V_{1}$ and $V_{2}$ are volume of gas at $T_{1}$ and $T_{2}$ temperature (in kelvin scale) respectively.

Here $V_{1}=158mL$ , $T_{1}=(273+25)K=298K$ and $V_{2}=450mL$

So $T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K$

849 K = (849-273) $^{0}\textrm{C}$ = 576 $^{0}\textrm{C}$

So final temperature of the gas is 576 $^{0}\textrm{C}$ .

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3 years ago

How can you write tht in mg ??

inessss [21]

Rris is how u right it Mg=? Because it ask u a question and then you put the equal sign and then you put the question mark because you don't know it yet

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3 years ago

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