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3 years ago

An object that has momentum can NOT also be _____.

Physics

2 answers:

arlik [135]3 years ago

7 0

Answer:

Explanation:

if the object has momentum it can be any other answer except at rest. if it's at rest, it does not have momentum

stiks02 [169]3 years ago

6 0

Answer: B

Explanation:

The equation to find momentum is velocity*mass. Without velocity, there would be no momentum. Therefore the object CAN NOT be at rest.

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Answer:

Kinetic energy increases because iron shavings move in the direction of magnetic force.

Potential energy decreases, and kinetic and thermal energy increase.

Potential energy increases because movement is in the opposite direction of the magnetic field.

They seek a rail line not affected by friction.

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3 years ago

The change in state of a liquid to a gas

ioda

evaporation (if that's to fill in the blanks question)

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3 years ago

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An automobile engine has an efficiency of 19.0%. If it produces 23.0 kJ of mechanical work per second, the heat rejected per sec

creativ13 [48]

Answer:

(e) 98,1 KJ

Explanation:

The engine produces 19%; it means, it rejects 81% of energy. ⇒ 81/19=4.26 times.

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3 years ago

An adiabatic nozzle has an inlet area of 1 m^2 and an outlet area of 0.25 m^2. Water enters the nozzle at a rate of 5 m^3/s and

svlad2 [7]

Answer:

v=20m/S

p=-37.5kPa

Explanation:

Hello! This exercise should be resolved in the next two steps

1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed

Q=VA

for he exitt

Q=flow=5m^3/s

A=area=0.25m^2

V=Speed

solving for V

$V=\frac{Q}{A} \\V=\frac{5}{0.25} =20m/s$

velocity at the exit=20m/s

for entry

$V=\frac{5}{1} =5m/s$

To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.

$\frac{P1}{\alpha } +\frac{v1^2}{2g} =\frac{P2} {\alpha } +\frac{v2^2}{2g}$

where

P=presure

α=9.810KN/m^3 specific weight for water

V=speed

g=gravity

solving for P1

$(\frac{p1}{\alpha } +\frac{V1^2-V2^2}{2g})\alpha =p2\\(\frac{150}{9.81 } +\frac{5^2-20^2}{2(9.81)})9.81 =p2\\P2=-37.5kPa$

the pressure at exit is -37.5kPa

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3 years ago

Whats the answer to 45 + 54 ÷ p - q

Lynna [10]

There’s nothing to answer to

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3 years ago