Question

An ice skater with a mass of 50 kg is gliding acrossthe ice at a speed of 8 m/s when herfriend comes up from behind and gives her a push,causing her speed to increase to 12m/s. How much work did the friend do on the skater

Answer 1

Answer:

$W=2KJ$

Explanation:

From the question we are told that:

Mass $M=50kg$

Initial Velocity $v_1=8m/s$

Final Velocity $v_2=12m/s$

Generally the equation for Work-done is mathematically given by

W=\triangle K.E

Therefore

 $W=0.5M(v_2^2-v_1^2)$

 $W=0.5*50(12^2-8^2)$

 $W=2KJ$