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grandymaker [24]

3 years ago

12

A steel wire of cross_ sectional area 2x10-5 m2 is stretched through 2mm by a force of 4000 N. find the young's modulus of the w

ire . the length of the wire is 2m.
please answer me.

1 answer:

UNO [17]3 years ago

7 0

Answer:

hi how are you doing today Jasmine

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How much heat is released when 12.0 grams of helium gas condense at 2.17 K? The latent heat of vaporization of helium is 21 J/g.

uranmaximum [27]

To determine the heat released by the process of condensation, we simply multiply the amount of the gas that condensed to the latent heat of vaporization. We do as follows:

Heat released = 21 J/g (12.0 g ) = 252 J of heat released

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4 years ago

a. Define Valency. b. Write the symbol and valency of the following : (i) Oxygen (ii) potassium 7. a. Magnesium burns in Oxygen

sweet-ann [11.9K]

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Oxygen-Symbol-O Potassium Symbol-K

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4 years ago

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What type of objects cannot pull to magmets

boyakko [2]

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brass, copper, zinc and aluminum, wood, glass, and plastic

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3 years ago

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My Notes A container is divided into two equal compartments by a partition. One compartment is initially filled with helium at a

Ostrovityanka [42]

Answer:

$final-temperature = T_{f} = 252.51K$

Explanation:

we can solve this problem by using the first law of thermodynamics.

$\Delta U= Q-W$

Q= heat added

U= internal energy

W= work done by system

$E_{final}= E_{initial}$

<u> $C_{v} (N_{2}) C_{v}(He) T_{f} =C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}$ (1)</u>

$C_{v}(N_{2})=1.04\frac{KJ}{Kg K}$

$C_{v}(He)=5.193\frac{KJ}{Kg K}$

now

From equation 1

$T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}$

$T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}$

$T_{f} = 252.51K$

4 0

4 years ago