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photoshop1234 [79]
3 years ago
11

A tightly sealed 5.0-l flask contains 781 mm hg of ar at 19 °c. the flask is heated until the pressure is doubled. what is the t

emperature of the gas?
Chemistry
1 answer:
sashaice [31]3 years ago
3 0
Get on mathpapa is shows you the answer and how to explain it
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competed in a track meet and you run the 1500m race in 403 s. what was your average speed in miles per hour
laila [671]

Answer:

403 Seconds in Minutes is about 6 minutes.

Explanation:

Now, because I don't know if you're labeling your 1500 as meters or miles, I'm assuming it's miles.

I'm going to take a gander at your question.

Since you're technically going so fast for some odd reason.

Your answer should most definitely be 403 MPH

6 0
3 years ago
What is the basic principle of chromatography process ​
Elina [12.6K]

process by which one separates compounds from one another by passing a mixture through column that retains some compounds longer than others.

4 0
3 years ago
What do the roman numberals mean?
Bezzdna [24]

Explanation:

c I think I am not sure so yh

3 0
3 years ago
Pls help me with this
Zina [86]

Answer:

[I_2]=[Br]=0.31M

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

I_2+Br_2\rightleftharpoons 2IBr

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}

Thus, we solve for x as show below:

\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M

Therefore, the concentrations of both bromine and iodine are:

[I_2]=[Br]=2.0M-1.69M=0.31M

Regards!

8 0
3 years ago
If a gas displays a solubility of 0.00290M at a partial pressure of 125 kPa, what is the proportionality constant for this gas i
alexgriva [62]

Answer:

The proportionality constant ( Henry’s constant) = 2.32 * 10^-5 M/kPa

Explanation:

Here in this question, we are concerned with calculating the proportionality constant for this gas.

Mathematically, we can get this from Henry law

From Henry law;

Concentration = Henry constant * partial pressure

Thus Henry constant = concentration/partial pressure

Henry constant = 0.00290 M/125 kPa = 2.32 * 10^-5 M/kPa

5 0
3 years ago
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