Answer:
9.61 % error
Explanation:
The formula for percent error is as follows:
% error = (experimental value - theoretical value) ÷ theoretical value × 100%
So to calculate the percent error all you have to you is plug in your values.
% error = (4.45cm - 4.06cm)/4.06 × 100%
= 0.39/4.06 × 100%
= 0.0961 × 100%
= 9.61 % error
3.8mL of 0.42 phosphoric acid is required.
Reaction
2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl
moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol
moles of H3Po4
= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2
= 0.00106 mol
V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL
V of H3PO4=3.8mL
To know more about calculation in milliliters refer to:-
brainly.com/question/23276655
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I think Domain would be the best choice because your optoins dont make much sense :/
<h2>Bombarded α-Particles on a thin Sheet of Gold
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Explanation:
- Rutherford Atomic Model is also known as " The plum pudding model"
- Rutherford’s in his experiment bombarded α-particles which are of high energy on a thin sheet of gold nearly 100 nm of thickness and observed the trajectory path of these particles after interacting with the foil of gold.
- He placed a fluorescent screen of zinc sulfide around the thin gold foil to study the trajectory path of the α-particles and its deflection.
- Most of the α-particles passed through the gold foil were not deflected as most of the internal space of the atom was empty.
- The result was that the positive charge of the atom occupies very little space.