F=m*a
F=65 kg *9.8 m/s^2
F=637 N (Newtons) — this is the weight
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c .... work is force x distance as a definition
The correct answer is 1.07m.
The area surrounding an electric charge where its impact may be felt is known as the electric field. When another charge enters the field, the presence of an electric field may be felt. The electric field will either attract or repel the charge depending on its makeup. Any electric charge has a property known as the electric field. The charge and electrical force working in the field determine the strength or intensity of the electric field.
Here, is the charge per unit length, r is the distance from the wire, and
is the free space permittivity ε_0. Electric field due to the long straight wire is,
E= λ/2πε_0r
Rearrange the equation for r.
r=λ/2πε_0E
Substitute 2.41 N/C for E,
E=1.44×10^-10C/m
λ=8.85×10^-12C^2/Nm^2
r=(1.44×10^-10C/m)/(2(3.14)(8.85×10^-12C^2/Nm^2)(2.41N/C))
r=1.07m
At a distance of 1.07 m the magnitude of electric field is 2.41 N/C.
To learn more about electric field refer the link:
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Answer: 4.2 m
Explanation:
The time taken by the tennis ball to cover vertical displacement 1.30 m would be the same time in which ball would cover horizontal distance.
Initial velocity of the ball, u = 8.08 m/s in horizontal direction.
Initial velocity in the vertical direction is 0.
consider upward direction as positive and downward direction as negative. The ball free falls under gravity in the vertical direction.
Using the second equation of motion,
y = u t + 0.5 at²
⇒-1.30 m = 0 + 0.5 ×(-9.8m/s²) t²
⇒t = 0.52 s
There is no external force acting in the horizontal direction, thus horizontal distance covered is:
s = u t ⇒ s = 8.08 m/s × 0.52 s = 4.2 m
Thus, the tennis ball lands 4.2 m far away.
