Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv

Substitute the suitable values in the above equation.

v₁ = 2.57 m/s
To solve this problem it is necessary to apply the concepts given by Malus regarding the Intensity of light.
From the law of Malus intensity can be defined as

Where
Angle From vertical of the axis of the polarizing filter
Intensity of the unpolarized light
The expression for the intensity of the light after passing through the first filter is given by

Replacing we have that


Re-arrange the equation,

Re-arrange to find \theta





The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°
Explanation:
It took
for the sound to reach the 1st wall and at the same time time, the same sound took
to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let
be the distance of the person to the 1st wall and
be the distance to the 2nd wall. So the distance between the walls X is


Explanation:
The kinetic energy is basically the energy possesses by virtue of a body's motion
1. The truck moving to the quarry
let the mass be x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(x)*20^2
KE=1/2(x)400
KE=200x
2. The truck leaving to the quarry
let the mass be 2x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(2x)*20^2
KE=1/2(2x)400
KE=400x
From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy