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Nookie1986 [14]
4 years ago
15

A piccolo and a flute can be approximated as cylindrical tubes with both ends open. The lowest fundamental frequency produced by

one kind of piccolo is 522.5 Hz, and that produced by one kind of flute is 256.9 Hz. What is the ratio of the piccolo's length to the flute's length?
Physics
1 answer:
Alexandra [31]4 years ago
3 0

Answer:

ratio of the piccolo's length to the flute's length is 0.4916

Explanation:

given data

frequency of piccolo = 522.5 Hz

frequency of flute = 256.9 Hz

to find out

ratio of the piccolo's length to the flute's length

solution

we get here length of tube that is express as

length of tube = velocity of sound ÷ fundamental frequency .......................1

so here ratio of Piccolo length to flute that is

\frac{L\ picco}{L\ flute}  = \frac{f\ flute}{f \ piccolo}

\frac{l \ piccolo}{L\ flute} = \frac{256.9}{522.5}  =  0.4916

so ratio of the piccolo's length to the flute's length is 0.4916

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A 62.2 kg ice skater moving to the right with a velocity of 2.66 m/s throws a 0.145 kg snowball to the right with a velocity of
Travka [436]

Answer:

Velocity of skater after throwing the snowball is 2.57 m/s

Explanation:

Given :

Mass of skater, M = 62.2 kg

Mass of snowball, m = 0.145 kg

Velocity of snowball relative to ground, v = 39.3 m/s

Consider v₁ be the velocity of skater after throwing the snowball.

According to the problem, initially the velocity of skater and snowball is same. So,

Velocity of skater before throwing snowball, u = 2.66 m/s

Applying conservation of momentum,

Momentum before throwing snowball = Momentum after throwing snowball

(M + m) u = Mv₁ + mv

v_{1}=\frac{(M+m)u-mv}{M}

Substitute the suitable values in the above equation.

v_{1}=\frac{(62.2+0.145)2.66-0.145\times39.3}{62.2}

v₁ = 2.57 m/s

3 0
4 years ago
THE VELOCITY RATIO OF A SINGLE MOVABLE PULLEY IS TWO​
Andrews [41]

Answer:

???

Explanation:

7 0
3 years ago
Unpolarized light with intensity 370 W/m2 passes first through a polarizing filter with its axis vertical, then through a second
vampirchik [111]

To solve this problem it is necessary to apply the concepts given by Malus regarding the Intensity of light.

From the law of Malus intensity can be defined as

I' = \frac{I_0}{2} cos^2 \theta

Where

\theta =Angle From vertical of the axis of the polarizing filter

I_0 = Intensity of the unpolarized light

The expression for the intensity of the light after passing through the first filter is given by

I = \frac{I_0}{2}

Replacing we have that

I = \frac{370}{2}

I = 185W/m^2

Re-arrange the equation,

I'= \frac{I_0}{2}cos^2\theta

Re-arrange to find \theta

cos^2\theta = \frac{2I'}{I_0}

cos^2\theta = \frac{2*138}{370}

\theta = cos^{-1}(\sqrt{\frac{2*138}{370}})

\theta = 0.5282rad

\theta = 30.27\°

The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°

4 0
3 years ago
a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate
Karolina [17]

Explanation:

It took t_1 =1.5\:\text{s} for the sound to reach the 1st wall and at the same time time, the same sound took t_2 = 2.5\:\text{s} to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let x_1 be the distance of the person to the 1st wall and x_2 be the distance to the 2nd wall. So the distance between the walls X is

X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)

\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}

6 0
3 years ago
6.A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of
Karolina [17]

Explanation:

The kinetic energy is basically the energy possesses by virtue of a body's motion

1. The truck moving to the quarry

let the mass be x

and the velocity is given as 20m/s

we know that the kinetic energy is given as

KE=1/2mv^2

KE=1/2(x)*20^2

KE=1/2(x)400

KE=200x

2. The truck leaving to the quarry

let the mass be 2x

and the velocity is given as 20m/s

we know that the kinetic energy is given as

KE=1/2mv^2

KE=1/2(2x)*20^2

KE=1/2(2x)400

KE=400x

From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy

4 0
3 years ago
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