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3 years ago

14

Emily's house lies on the San Andreas Fault, and she wants to protect herself against earthquakes. What is one step she can take

?
A.
Educate herself on ground deformation that occurs before earthquakes.
B.
Check her building’s foundation to ensure it is resistant to shaking caused by moving tectonic plates.
C.
Buy a device that can predict earthquakes before they occur.
D.
Be prepared to evacuate if steam or ash cloud eruptions are visible.

1 answer:

Digiron [165]3 years ago

5 0

Answer:

B. Check her building’s foundation to ensure it is resistant to shaking caused by moving tectonic plates

Explanation:

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A family is skating at an ice rink. The 58.2 kg mother is holding the

MariettaO [177]

Answer:

When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.

Explanation:

use this formula :

$a_{y}$ = $\frac{Fdadshandy}{msys}$

then you fill it in :

$a_{y}$ = $\frac{100N}{35.5kg+58.2kg}$

$a_{y}$ = $\frac{100N}{93.7kg}$

$a_{y}$ = $1.0672$ $m/s^{2}$

then you multiply that with the daughters weight :

$T_{2} x= m_{2} a_{y}$

$T_{2} x = 35.5kg (1.0672 m/s^{2})$

$T_{2} x = 37.89N$

and that's the answer :) : 37.89N

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3 years ago

The combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8

qwelly [4]

Answer: f = -12 cm

Explanation: <u>Combined</u> <u>lenses</u> is an array of simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.

When two lenses are in contact and are thin, focal lengths are related as:

$\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}$

If there is a distance between the lenses, the focal length will be:

$\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}$

Since the lenses in the question above are thin and in contact, the focal length of one of them will be:

$\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}$

$\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}$

$\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}$

$\frac{1}{f_{2}} =\frac{-2}{24}$

$f_{2}=$ -12

The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.

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3 years ago

A ladder 7.85 m long leans against the side of a building. If the ladder is inclined at an angle of 79.5° to the horizontal, wha

Slav-nsk [51]

Jsdjdjjjdjdjd

Explanation:Sjsjsjsmjsjddhdmddjdidujddjdujddmjsisisi daddy dickkkdududjdjsjsusjsususuksuckmpormmjsjdjsjxjxxjjjsusjhs

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4 years ago

Comment on whether or not the following label on a consumer product should be cause for concern: CAUTION: The mass of this produ

Levart [38]

Answer:

Yes, it should be.

4 0

4 years ago

Light propagating in air strikes the surface of a lake. The reflected ray makes 62° angle with the normal. What angle does the r

blondinia [14]

Answer:

(a) 42°

Explanation:

According to the law of reflection:

Angle of incidence = Angle of reflection

So, angle of reflection = 62°

Angle of incidence = 62°

For refraction,

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 62.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (water, n=1.33)

${n_i}$ is the refractive index of the incidence medium (air, n=1)

Hence,

$1\times {sin62.0^0}={1.33}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.6639$ = 42°

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3 years ago