Answer:
A & B
Explanation:
A & B Would be the right answer since Morse code cannot be represented through the height of the fire.
1). Sequence from the Sun:
Inner planets:
Mercury
Venus
Earth
Mars
Outer planets:
Jupiter
Saturn
Uranus
Neptune
2). The farther a planet is from the sun, the longer it takes
to orbit the sun. Mercury ... 88 days. Earth ... 365 days.
Jupiter ... 12 years. Neptune ... 165 years.
3). Mercury & Venus ... no moons
Earth - 1
Mars - 2
Jupiter - more than 65
4). Mercury ... cratered, no atmosphere
Venus ... cratered, thick cloudy atmosphere
Mars ... dry, cratered, slight atmosphere, like 1% or Earth's
Jupiter, Saturn, Uranus, Neptune
We can't see any surface. If any of them even
HAS a surface, it's thousands of miles under a
thick atmosphere of methane gas.
5). Missing from the list
6). Here's a list from the biggest planet to the smallest one.
The numbers in parentheses are the radius of the planet --
half of the diameter:
Jupiter (69,911 km / 43,441 miles) – 1,120% the size of Earth
Saturn (58,232 km / 36,184 miles) – 945% the size of Earth
Uranus (25,362 km / 15,759 miles) – 400% the size of Earth
Neptune (24,622 km / 15,299 miles) – 388% the size of Earth
Earth (6,371 km / 3,959 miles)
Venus (6,052 km / 3,761 miles) – 95% the size of Earth
Mars (3,390 km / 2,460 miles) – 53% the size of Earth
Mercury (2,440 km / 1,516 miles) – 38% the size of Earth
7). At least seven of the planets rotate in the same direction.
There's something different about one of them ... it may be Uranus
but I'm not sure. You'll have to look this up.
8). Saturn has the famous rings, that you can almost see
with only binoculars.
Spacecraft sent to observe the outer planets have detected
very thin rings around Uranus and Neptune.
9). Included in #6.
10). I don't have complete info. Generally, the closer the planet
is to the sun, the hotter it is. But there are a few exceptions.
I think Venus ... the second one from the sun, is actually hotter
than Mercury.
11). Just about every language has its own name for each planet.
12). "Terrestrial" means "like Earth" ("Terra").
The terrestrial planets are the ones that have solid surfaces
and are made of rock.
Mercury, Venus, Earth, and Mars.
13). "Jovian" means "like Jupiter".
Either no solid surface, or very small, inside a big deep gas ball.
Jupiter, Saturn, Uranus, Neptune.
Heat supplied to the gold will raise the temperature of the gold from 20 degree Celsius to 90 degree Celsius.
Mass of the gold (m) = 0.072 kg
Temperature change (ΔT) = 90 - 20 = 70 degree Celsius
Specific heat capacity of the gold (c) = 136 J/kg C
Heat supplied = m × c × ΔT
Heat supplied = 0.072 × 136 × 70
Heat supplied = 685.44 Joules
Hence, the heat supplied to the gold to raise the temperature from 20 degree Celsius to 90 degree Celsius = 685.44 Joules
Answer:
The voltage bewtween the plates will be 9.5V
Explanation:
Facts:
The capacitance of a parallel plate capacitor having plate area A and plate separation d is C=ϵ0A/d.
Where ϵ0 is the permittivity of free space.
A capacitor filled with dielectric slab of dielectric constant K, will have a new capacitance C1=ϵ0kA/d
C1=K(ϵ0A/d)
C1=KC ----------- 1
Where C is the capacitance with no dielectric and C1 is the capacitance with dielectric.
The new capacitance is k times the capacitance of the capacitor without dielectric slab.
This implies that the charge storing capacity of a capacitor increases k times that of the capacitor without dielectric slab.
Given points
• The terminal voltage of the battery to which the capacitor is connected to charge V=25V
• A dielectric slab of paraffin of dielectric constant K=2 is inserted in the space between the capacitor plates after the fully charged capacitor is disconnected
The charge stored in the original capacitor Q=CV
The charge stored in the original capacitor after inserting dielectric Q1=C1V1
The law of conservation of energy states that the energy stored is constant:
i.e Charge stored in the original capacitor is same as charge stored after the dielectric is inserted.
Q = Q1
CV = C1V1
CV = C1V1 -------2
We derived C1=KC from equation 1. Inserting this into equation 2
CV = KCV1
V1 = (CV)/KC
V/K
= 21/2.2
= 9.5
Solution
Let a cell of emf E be connected across the entire length L of a potentiometer wire . Now , if the balance point is obtained at a length l during measurement of an unknown voltage
.
The balance point is not on the potentiometer wire - this statement means that
. In that case ,
l > L
V > E
