Can someone help me i'm confused
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The image of the bonds are missing, so i have attached it.
Answer:
A) - Sigma bond
-Sp³ and Sp³
- None
B) - Sigma and pi bond
- Sp² of C and p of O
- p of C and P of O
Explanation:
A) For compound 1;
- the molecular orbital type is sigma bond due to the end-to-end overlapping.
- Atomic orbitals in the sigma bond will be Sp³ and Sp³
- Atomic orbitals in the pi bond would be nil because there is no pi bond.
B) For compound 2;
- the molecular orbital type is sigma and pi bond
-Atomic orbitals in the sigma bond would be Sp² of C and p of O
- The Atomic orbitals in the pi bond will be; p of C and p of O
When Carboxylic Acid is treated with Alcohols in the presence of acid as a catalyst it produces corresponding Esters. This reaction is called as Esterification.
Also, this reaction is a reversible reaction and the ester formed can also hydrolyze to produce Carboxylic acid and Alcohol. This reverse reaction is called as transesterification.
The formation of Ethyl Acetate from Acetic Acid and Ethanol in the presence of acid is shown below,
Also, this reaction is a reversible reaction and the ester formed can also hydrolyze to produce Carboxylic acid and Alcohol. This reverse reaction is called as transesterification.
The formation of Ethyl Acetate from Acetic Acid and Ethanol in the presence of acid is shown below,
Answer:
The partial pressure of BrCl at equilibrium is 0.08 atm.
Explanation:
The equilibrium constant of the reaction is given by =
initial
0 0 0.500 atm
At equilbrium
p p (0.500-2p)
The equilibrium constant's expression of the reaction is given by ;
Solving for p:
p = 0.21 atm
The partial pressure of BrCl at equilibrium is:
(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]