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3 years ago

describe the relationship between the energy of an electron, and its probable distance away from the nucleus of an atom?

1 answer:

8 0

Answer: The energy of an electron depends on its location with respect to the nucleus of an atom. The higher the energy of an electron in an atom, the farther is its most probable location from the nucleus.

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Compare and contrast the elements Potassium, K, and Neon, Ne. Use at least ten comparisons or descriptions.

vovikov84 [41]

Answer:

K is a group 1 element while Ne is a group 0 element

K is a good reducing agent while Ne is inert

K is metal while Ne is a gas

K has one valence electron while Ne has no valence electron

Explanation:

4 0

3 years ago

ML? PLEASEEE HELP<br> What is the answer

Fofino [41]

22.5 milliliters :)))

6 0

3 years ago

Read 2 more answers

Determine the mass of 2.5 cups of water if the density of water is 1.00 g/cm^3 and 1 cup = 240 mL

jarptica [38.1K]

1) we find out the volume of the water.
Remember: 1 ml=1 cm³
Volume of the water=number of cups x volume of one cup.
Volume of the water=2.5(240 ml)=600 ml=600 cm³

Density=mass/volume ⇒ mass=density x volume

2) we calculate the water mass of 600 cm³ of water.
mass=density x volume
mass=(1 g/cm³)(600 cm³)=600 g.

Answer: the mass of 2.5 cupas of water is 600 g.

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3 years ago

How does distillation separate a solvent from a solute?

lord [1]

Answer:

Distillable mixtures may contain a solid in a liquid. This method takes advantage of the boiling point of the substances.

In this way, for the distillation to take place correctly, the mixture must be boiled until the boiling point of the solvent is reached, which will then become steam and can be led to a cooled container, in which it will condense and recover its liquidity. On the other hand the solute will remain in the container without alterations; having in both cases pure substances, free of the initial mixture.

5 0

3 years ago

You are given a solid that is a mixture of Na2SO4 and K2SO4. A 0.205-g sample of the mixture is dissolved in water. An excess of

Svetach [21]

Answer:

Mass of SO₄⁻² = 0.123 g.

Mass percentage of SO₄⁻² = 41.2%

Mass of Na₂SO₄ = 0.0773 g

Mass of K₂SO₄ = 0.1277 g

Explanation:

Here we have

We place Na₂SO₄ = X and

K₂SO₄ = Y

Therefore

X +Y = 0.205 .........(1)

Therefore since the BaSO₄ is formed from BaCl₂, Na₂SO₄ and K₂SO₄ we have

Amount of BaSO₄ from Na₂SO₄ is therefore;

$X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}$

Amount of BaSO₄ from K₂SO₄ is;

$Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}$

Molar mass of

BaSO₄ = 233.38 g/mol

Na₂SO₄ = 142.04 g/mol

K₂SO₄ = 174.259 g/mol

$X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}$ = $X\times\frac{233.38 }{142.04}$ = 1.643·X

$Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}$ = $Y\times\frac{233.38 }{174.259 }$ = 1.339·Y

Therefore, we have

1.643·X + 1.339·Y = 0.298 g.....(2)

Solving equations (1) and (2) gives

The mass of SO₄⁻² in the sample is given by

Mass of sample = 0.298

Molar mass of BaSO₄ = 233.38 g/mol

Mass of Ba = 137.327 g/mol

∴ Mass of SO₄ = 233.38 g - 137.327 g = 96.05 g

Mass fraction of SO₄⁻² in BaSO₄ = 96.05 g/233.38 g = 0.412

Mass of SO₄⁻² in the sample is 0.412×0.298 = 0.123 g.

Percentage mass of SO₄⁻² = 41.2%

Solving equations (1) and (2) gives

X = 0.0773 g and Y = 0.1277 g.

8 0

3 years ago