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NeX [460]
3 years ago
5

About how often does a 1-kilometer object strike the earth? about how often does a 1-kilometer object strike the earth? every ye

ar every million years every billion years
Physics
1 answer:
stiv31 [10]3 years ago
5 0
The correct option is the second one, which is: Every million years.

 The impact of a 1-kilometer object on our planet, would cause significant consequences. As the astronomers have found in other terrestrial bodies, this kind of impact creates largers craters on the surface.
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A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

  • Mass of the first puck = m_1\ =\ 5\ kg
  • Mass of the second puck = m_2\ =\ 3\ kg
  • initial velocity of the first puck = u_1\ =\ 3\ m/s.
  • Initial velocity of the second puck = u_2\ =\ -1.5\ m/s.

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = v_2\ =\ 2.31\ m/s.

Let v_1 be the final velocity of first puck after the collision.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = 25\times 10^{-3}\ sec

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0
3 years ago
How long does a 50 kW pump motor have to run to pump 500 cubic meters of water from a 180m deep mine
Ghella [55]

Answer:

t = 17658 s = 294.3 min = 4.9 h

Explanation:

The general formula for power is:

P = \frac{W}{t}

where,

P = Power of the Motor = 50 KW = 50000 W

W = Work Done by Motor = Change in P.E of Water = mgh

g = acceleration due to gravity = 9.81 m/s²

m = mass of  water = ρV

h = depth of water = 180 m

ρ = density of water = 1000 kg/m³

V = Volume of Water = 500 m³

t = time taken = ?

Therefore,

P = \frac{mgh}{t}=\frac{\rho Vgh}{t}\\\\t = \frac{\rho Vgh}{P}\\\\t = \frac{(1000\ kg/m^3)(500\ m^3)(9.81\ m/s^2)(180\ m)}{50000\ W}\\\\

<u>t = 17658 s = 294.3 min = 4.9 h</u>

6 0
3 years ago
HELP ME DO THIS QUESTION PLEASE ​
raketka [301]

Answer:

i dont know

Explanation:

but what you can do is ask you mom or dad to get you a tutor to help you

7 0
3 years ago
A 60 kg skydiver is falling at a terminal velocity of 50 m/s.
marishachu [46]

Answer:

The gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.

the acceleration a = 7.8 m/s²

Explanation:

Given that :

the mass of the skydiver = 60 kg

Velocity = 50 m/s

Thus;  gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.

Also; the air resistance is acting upward and the resultant of both forces = mass×acceleration

So;

mg-R = ma

60(9.8) - 120 = 60(a)

588 -120 = 60a

468 = 60a

a = \frac{468}{60}

a = 7.8 m/s²

Hence, the acceleration a = 7.8 m/s²

5 0
3 years ago
The temperature of a 2.0kg block increases by 5C when 2000 J of thermal energy are added to the block. What is the specific heat
vitfil [10]

Explanation:

Q=mc(T2-T1)

or

q = mcΔT ,

where m is the mass of the sample,

c is the specific heat,

and ΔT is the temperature change.

Q=2.0 × 2000 × 5

Q=20000J⋅kg −1 ⋅K −1

I hoped I helped pls rate as brainliest

7 0
2 years ago
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