Answer:
377 m
Explanation:
number of turns, N = 65
θ = 36°
B1 = 200 micro Tesla
B2 = 600 micro tesla
t = 0.4 s
induced emf, e = 80 mV
Let a be the side of the square coil.
a = 1.45 m
Total length of the wire, L = N x 4a = 65 x 4 x 1.45 = 377 m
Thus, the length of the wire is 377 m.
I don't have research to back it up, but exercise is working out. Fitness is taking care of your body, that includes working out and things like eating right.
(h + .16) m g = 1/2 k x^2 total PE of block relative to where it stops
(h + .16) .82 * 9.8 = .5 * 120 * .16^2 PE released = PE of spring
8.04 h + 1.29 = 1.536
h = (1.536 - 1.29) / 8.04 = .031 m = 3.1 cm
-- Electric field lines DO never cross. <em>(A)
</em>
-- Electric field lines that are close together DO indicate a stronger electric field. <em>(B)
</em>
-- Electric field lines DO not affect the charge that created them. <em>(C)</em>
-- Electric field lines DON'T begin on north poles and end on south poles. North and South "poles" are the way we talk about magnets, not electric charges.
