3 years ago

A 12 N net force is applied to an object as it moves a distance of 3.0 m: Use the

Physics

1 answer:

OLEGan [10]3 years ago

3 0

Answer:

4 joules

Explanation:

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Assume the following values: d1 = 0.880 m , d2 = 1.11 m , d3 = 0.560 m , d4 = 2.08 m , F1 = 510 N , F2 = 306 N , F3 = 501 N , F4

dsp73

Answer:

= 2630.6 N.m

Explanation:

(FR)x = ΣFx = -F4 = -407 N

(FR)y = ΣFy =-F1-F2 -F3 = -510 - 306 - 501 = -1317 N

(MR)B =ΣM + Σ(±Fd)

= MA + F1(d1 +d2) + F2d2 - F4d3

= 1504 + 510(0.880+1.11) +306(1.11) - 407(0.560)

= 2630.64 N.m (counterclockwise)

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3 years ago

What is mass loss and how does it figure in the death of a star? is the sun undergoing mass loss

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111122 is the mass of the star

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3 years ago

When motion is measured a starting point is called ?

AleksAgata [21]

The starting point for measuring motion is called : The Reference Point.

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3 years ago

Aktiviti ( 6<br>b) Bina ayat menggunakan penjodoh bilangan berdasarkan<br>situasi di bawah.<br><br>

Anna007 [38]

Answer:

mananyeeeee situasiii

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3 years ago

A package of aluminum foil contains 50. Ft2 of foil, which weighs approximately 7.0 oz . Aluminum has a density of 2.70 g/cm3. W

kumpel [21]

We know density = Mass / Volume

So Volume = Mass/Density

Volume = Area * Thickness

$Area = 50 ft^2 = 4.645152 m^2\\ \\Mass = 7 oz = 0.198447 kg\\ \\Density = 2.70 g/cm^3 = 2700 kg/m^3\\ \\Substituting \\ \\4.645152 *t = \frac{0.198447}{2700} \\ \\t = 1.58*10^{-5}m = 1.58*10^{-2}mm$

So the approximate thickness of the foil in millimeters = $1.58*10^{-2}mm$

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3 years ago