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3 years ago

The speed of the wooden bar is changed so that the bar hits the water fewer times each second.

Physics

1 answer:

Hitman42 [59]3 years ago

3 0

Answer:

c - the frequency of the waves decreases

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Please help me !!

avanturin [10]

The correct answer is B

5 0

3 years ago

Minute after minute, hour after hour, day after day, ocean waves continue to splash onto the shore. Explain why the beach is not

MAVERICK [17]

Answer: C. Ocean waves can only bring energy to the shore; the particles of the medium (water) simply oscillate about their fixed position.

Explanation:

The reason why the beach is not completely submerged and the reason why the middle of the ocean has not been depleted of its water supply is due to the fact that water isn't transported by ocean waves.

It should be noted that even a single drop of water cannot be brought by the ocean wave to the shore from the middle of the ocean.

The only thing that the ocean waves can bring to the shore is energy. Hemce, the water particles oscillate in their fixed position which is vital in making sure that the beach isn't piled up with water.

4 0

3 years ago

A motor is used to produce

Tpy6a [65]

Your answer would be 4.0 hz.

4 0

3 years ago

mass is 5 lb attached to a rope wound around a pulley. The radius of the pulley is 3 in. If the mass falls at a constant velocit

suter [353]

Answer:

The power transmitted to the pulley is 0.0455 hp.

Explanation:

Given;

mass attached to the rope, m = 5 lb

radius of the pulley, r = 3 in

constant rate of fall of the mass, v = 5 ft/s

acceleration due to gravity, g = 32.2 ft/s²

1 lbf = 32.2 lb.ft/s²

The power transmitted to the pulley is calculated as;

P = Fv

P = (mg)v

$P = 5 \ lb \ \times \ 32.2 \ \frac{ft}{s^2} \ \times \ 5 \ \frac{ft}{s} \ \times \ \frac{1 \ lbf}{32.2 \ lb.ft/s^2} \ \ = 25 \ \frac{ft.lbf}{s} \\\\$

in horse power, the power transmitted is calculated as;

$P = \frac{25 \ ft.lbf}{s} \ \times \ \frac{1 \ hp}{550 \ ft.lbf/s} \ \ = 0.0455 \ hp$

Therefore, the power transmitted to the pulley is 0.0455 hp.

3 0

3 years ago

A playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the gro

Shtirlitz [24]

Answer:

1.94601 rad/s

Explanation:

$I_1$ = Moment of inertia of carousel = 124 kgm²

$\omega_1$ = Angular speed of carousel = 3.5 rad/s

$\omega_2$ = Angular speed of person

r = Radius of carousel = 1.53 m

m = Mass of person = 42.3 kg

Moment of inertia of person

$I_2=mr^2\\\Rightarrow I_2=42.3\times 1.53^2\\\Rightarrow I_2=99.02007\ kgm^2$

As the angular momentum is conserved in the system

$I_1\omega_1=(I_1+I_2)\omega_2\\\Rightarrow \omega=\frac{I_1\omega_1}{(I_1+I_2)}\\\Rightarrow \omega_2=\frac{124\times 3.5}{(124+99.02007)}\\\Rightarrow \omega_2=1.94601\ rad/s$

The angular speed of the carousel after the person climbs aboard is 1.94601 rad/s

5 0

3 years ago