65. Which of the following heavy metal is not

Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows:

Nezavi [6.7K]

The theoretical yield of urea : = 227.4 kg

<h3>Further explanation</h3>

Given

Reaction

2NH3(aq)+CO2(aq)→CH4N2O(aq)+H2O(l)

128.9 kg of ammonia

211.4 kg of carbon dioxide

166.3 kg of urea.

Required

The theoretical yield of urea

Solution

mol Ammonia (MW=17 g/mol)

=128.9 : 17

= 7.58 kmol

mol CO₂(MW=44 g/mol) :

= 211.4 : 44

= 4.805 kmol

Mol : coefficient of reactant , NH₃ : CO₂ :

= 7.58/2 : 4.805/1

=3.79 : 4.805

Ammonia as limiting reactant(smaller ratio)

Mol urea based on mol Ammonia :

=1/2 x 7.58

=3.79 kmol

Mass urea :

=3.79 kmol x 60 g/mol

= 227.4 kg

3 0

2 years ago

How many electrons are in a s-2 ion

Zielflug [23.3K]

Answer:

the ion will have additional 2 electrons so it will be 18

6 0

3 years ago

Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o

Gnom [1K]

Answer: The empirical formula for the given compound is $C_5H_7N$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

$C_xH_yN_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of $CO_2=21.363mg=21.363\times 10^3g=21363g$

Mass of $H_2O=6.125g=6.125\times 10^3g=6125g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, $\frac{12}{44}\times 21363=5826.27g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, $\frac{2}{18}\times 6125=680.55$ of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = $\frac{485.52}{97.73}=4.96\approx 5$

For Hydrogen = $\frac{680.55}{97.73}=6.96\approx 7$

For Nitrogen = $\frac{97.73}{97.73}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is $C_5H_7N_1=C_5H_7N$

7 0

3 years ago

Elements are simple ___

storchak [24]

Answer:

particles

atoms

broken

isotope

conductors

electricity

element

combined

3 0

2 years ago

Blood ph is kept near a value of 7.3 - 7.5 because of

Ede4ka [16]

Answer: Neutral Value

Explanation: pH of the blood is maintained at 7.0 to 7.5that is neutral value.

This is because if the pH of the is lower than the maintained value then it will become acidic .

Acidic pH can cause the medical urgency known as acidosis leading to vomiting, diarrhea etc.

If the pH becomes higher, then the blood will become basic in nature and it can also leas to the death of the person.

That is why the pH of the blood is maintianed at neutral value of 7.0 to 7.5

5 0

3 years ago

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