Answer:
See detailed explanation.
Explanation:
Hello.
In this case, since each place has specific conditions of temperature, humidity, altitude and others, it is important for the companies building houses to consider all of those factors because they could wear out or affect the customer's lifestyle as the years go by.
More specifically, for temperature, since customers tend to complain and concern about it, there are some strategies in order to control it:
- In terms of location, it is possible to locate the house near to threes covering the sun, build it in a higher altitude since the higher altitude the lower the environmental temperature or just look for a place wherein the temperature is almost constant, for instance, south America.
- In terms of design, it is possible to build the walls and roofs with isolating materials which very likely to keep the inner part of the house from high temperatures or just installing heaters inside them.
Of course, there may be more strategies in order to control it.
Best regards.
Answer:
1.209g of MgO participates
Explanation:
In this problem, we have 0.030 moles of MgO that participates in a particular reaction.
And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.
To convert moles to grams we need to use molar mass of the compound:
<em>1 atom of Mg has a molar mass of 24.3g/mol</em>
<em>1 atom of O has a molar mass of 16g/mol</em>
<em />
That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol
And mass of 0.030 moles of MgO is:
0.030 moles MgO * (40.3g/mol) =
<h3>1.209g of MgO participates</h3>
Answer:
when silver articles exposed to air silver racts with Sulphur present in the atmosphere and form a black layer of silver sulphide on the surface. copper articles get tarnished by reacting with air and water. due to this, a layer is formed over copper vessels.
Answer:
False
Explanation:
The values of the principal quantum number range from 1- infinity. This implies that there is no such thing as an energy level with n=0.
Hence this can not be an acceptable set of quantum numbers when n=0.
Answer:- Heat lost by the metal is 279.45 cal.
Solution:- This type of problems are solved by using the concept, heat given = - heat taken
Metal temperature is decreasing from 45.00 degree C to 11.08 degree C. It means the heat is lost by the metal and this heat lost by metal is gained by water and the calorimeter to raise their temperature.
the equation we use is, 
.
where, q is the heat energy, m is mass, c is specific heat and 
is change in temperature.
Combined mass of calorimeter and water is 250.0 g and the specific heat is 
.
for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C
for metal = 11.08 - 45.00 = -33.92 degree C
let's plug in the values in the above equation and calculate heat gained by combined system.
q=250.0g*\frac{1.035cal}{g.^0C}*1.08^0C
q = 279.45 cal
So, the heat lost by the metal is 279.45 cal.
