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madreJ [45]
3 years ago
5

Which is an empirical formula? C₂H₄ C₃H₆ P₂O₅ P₄O₆

Chemistry
1 answer:
Fofino [41]3 years ago
4 0

Answer:

C3H8

Propane/Formula

Explanation:

hope this helps

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For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is 110. kJ. Calculate the equlilibriunm c
mestny [16]

Answer:

Explanation:

The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:

ΔG = -RT ln K

<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>

<em />

Replacing (110kJ = 110000J):

110000J/mol = -8.314J/molK*303.15K ln K

-43.644 = lnK

1.11x10⁻¹⁹ = K

<em />

7 0
3 years ago
Which of the following most accurately represents John Dalton’s model of the atom? A. a tiny, solid sphere with an unpredictable
valkas [14]

The most accurately represented John Dalton's model of the atom is: C. a tiny, solid sphere with a predictable mass for a given element

<h3>Further explanation</h3>

The development of atomic theory starts from the first term conveyed by Greek scientists who suggested that every substance has the smallest particles so that the word atomos appears, which means it cannot be divided. So, John Dalton, a British scientist put forward the hypothesis about atoms, among others:

  • 1. The elements are composed of atoms which are small particles which cannot be subdivided
  • 2. Atoms that make up the same element have the same properties, mass, and size, while for different elements, the properties are also different
  • 3. Compounds are composed of two or more atoms in a fixed ratio
  • 4. In chemical reactions, atoms after and before a reaction cannot be destroyed, only separation and reassembly occur

Point 3 shows the relationship with The Law of Constant Composition of Proust so that further research on atoms is more developed

Dalton's hypothesis is described as a solid sphere like a very small shot put ball or a bowling ball based on Dalton's hobby in bowling

<h3>Learn more</h3>

Bohr's model of the atom

brainly.com/question/1625635

Rutherford performed the gold foil experiment

brainly.com/question/1859083

The part of an atom that is mostly empty space

brainly.com/question/4089014

Keywords: atom, Dalton, a solid sphere, The Law of Constant Composition

5 0
3 years ago
Read 2 more answers
1. Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16) w
erik [133]

From the fact that oxygen is in group 16 and carbon is in group 14, the structure of CO2 must be O=C=O. In methane, there is no bond between any of the hydrogen atoms. The structure of H2O2 is H–O–O–H.

Carbon is in group 14 hence it has four valence electrons and oxygen is in group 16 hence it has six valence electrons. This implies that each oxygen atom will share four electrons with carbon in a covalent bond to form the structure O=C=O.

In CH4, we know that carbon is tetravalent so it forms for bonds. Therefore, there is no bond between hydrogen atoms so it bonds with each hydrogen atom; hydrogen only forms one bond.

In H2O2, there is the peroxide ion that has the structure O-O. Hence, the correct structure of H2O2 is H–O–O–H.

Learn more: brainly.com/question/24775418

5 0
3 years ago
At room temperature iodine is a solid and bromine is a liquid.
vichka [17]

Answer:

<u>Kinetic particle theory</u>

Arrangement and motion of solid particles

-> Solid particles are packed closely with each other in an orderly manner. They vibrate vigorously in their fixed positions.

Arrangement and motion of liquid particles

-> Liquid particles are packed less closely with each other as compared to solid particles in a disorderly manner. They move around in a random motion; sliding past each other.

3 0
3 years ago
If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?
padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

4 0
3 years ago
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