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2 years ago

Calculate the hydrogen ion concentration in a 3.4 x 10-3 M solution of KOH.

Chemistry

1 answer:

notsponge [240]2 years ago

7 0

Explanation:

$KOH→K {}^{ + } + OH {}^{ - } \\ [OH {}^{ - } ] = 3.4 \times {10}^{ - 3} \\ k _{w} = [OH {}^{ - } ] [H {}^{ + } ] \\ 1 \times {10}^{ - 14} = 3.4 \times {10}^{ - 3} \times [H {}^{ + } ] \\ [H {}^{ + } ] = 2.94 \times {10}^{ - 12} \: M$

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Must show units and how they cancelli 1.) 175 km to um 3.) 385 nm to dm 5.) 492 um tom 7.) 52 x 103 dm to mm 9.) 321x 1035 mm to

morpeh [17]

Explanation:

1.) 175 km to μm

$1 km=10^9 \mu m$

$175 km=175\times 10^9\mu m=1.75\times 10^{11} \mu m$

3.) 385 nm to dm

$1 nm=10^{-8} dm$

$385 nm=385\times 10^{-8} dm=3.85\times 10^{-6} dm$

5.) 492 μm to m

1 μm = $10^{-6} m$

$492 \μm=492\times 10^{-6} m=4.92\times 10^{-4} m$

7.) $52\times 10^3$ dm to mm

1 dm = 100 mm

$52\times 10^3 dm=52\times 10^3\times 100 mm=5.2\times 10^{6}dm$

9.) $321\times 10^{35}$ mm to km

$1 mm = 10^{-6} km$

$321\times 10^{35} mm=321\times 10^{35}\times 10^{-6} km=3.21\times 10^{31} km$

11.) $456\times 10^3$ m to km

m = 0.001 km

$456\times 10^3m =456\times 10^3 m\times 0.001 km=456 km$

13.) $422\times 10^3$ m to nm

$1 m = 10^{9} nm$

$422\times 10^3 m=422\times 10^3\times 10^{9} nm=4.22\times 10^{14} nm$

15.) $4.87\times 10^{30}$ m to pm

$1 m = 10^{12} pm$

$4.87\times 10^{30} m=4.87\times 10^{30}\times 10^{12} pm=4.82\times 10^{42} pm$

17.) $5.26\times 10^3$ m to um

1 m = $10^{6} \mu m$

$5.26\times 10^3 m=5.26\times 10^3\times 10^6 \mu m=5.26\times 10^{9} \mu m$

19.) $1.25\times 10^{35}$ m to Mm

1 m = $10^{-6} Mm$

$1.25\times 10^{35} m=1.25\times 10^{35}\times 10^{-6} Mm=1.25\times 10^{-29} Mm$

21.) $4.22\times 10^3$ Tm to nm

$1 Tm = 10^{21} nm$

$4.22\times 10^3 Tm=4.22\times 10^3\times 10^{21} nm=4.22\times 10^{24} nm$

6 0

3 years ago

Submit Quiz Previous Page 1 of 4 Next Drag and drop each description to match the subatomic particle. Protons Neutrons Drag and

Pavel [41]

Answer:

Protons:

Positively charged particle

The number of these is the atomic number

All atoms of a given element have the same number of these

Neutrons:

Neutral particles

Isotopes of a given element differ in the number of these

The mass number is the number of these added to the number of protons

Explanation:

Protons (positively charged), neutrons (neutral) and electrons (negatively charged) are smaller than an atom and they are the main subatomic particles. The nucleus of an atom is composed of protons and neutrons, and the electrons are in the periphery at unknown pathways.

The Atomic number (Z) indicates the number of protons ( $P^{+}$ ) in the nucleus. Every atom of an element have the same atomic number, thus the same number of protons.

The mass number (A) is the sum of the number of protons ( $P^{+}$ ) and neutrons (N) that are present in the nucleus: A= Z + N

Isotopes are atoms of the same element which nucleus have the same atomic number (Z), and different mass number (A), it means the same number of protons ( $P^{+}$ ) and a different number of neutrons (N). For example, the oxygen in its natural state is a mixture of isotopes:

99.8% atoms with A= 16, Z=8, and N=8

0.037% atoms with A=17, Z=8, and N=9

0.204% atoms with A=18, Z=8, and N=10

3 0

3 years ago

How many protons are in 10 moles of gold? Please help! Thank you!

irinina [24]

3 is the answer hope it helps

3 0

3 years ago

Read 2 more answers

Una disolución contiene 40% de ácido acético en masa. La densidad de la disolución es de 1.049 g/mL a 20°C. Calcule la masa de á

s344n2d4d5 [400]

Answer:

52.45g

Explanation:

The computation of the mass of pure acetic acid in 125mL of this solution is shown below:

The percentage of mass would be equivalent to the g of solute in each 100g of water

As we know that

density = mass ÷ volume

So,

Volume = mass ÷ density

V = 100g / 1.049 (g / ml)

V = 95.328 mL

Now In every 95,328 ml of C_2H_4O_2 there are 40g of C_2H_4O_2

i.e.

each 125ml of C_2H_4O_2 there are 52.45g

SO,

x = 40g. 125ml ÷ 95.328

x = 52.45g

4 0

3 years ago

Is germahium a metal?

MA_775_DIABLO [31]

Germanium is classified as a metalloid or semi-metal . (:

4 0

3 years ago