How many liters of chlorine are needed to produce 5.64 moles of aluminum chloride? Need help ASAP
1 answer:
Answer:
190 L
Explanation:
Given that:
Number of moles = mass/molar mass
number of moles = 5.64
molar mass of aluminum chloride = 133.34 g/mol
∴
The balanced equation is:
2 Al + 3 Cl2 --> 2AlCl3.
From above reaction:
5.64 mole of AlCl3 reacts with 3 mole Cl2 to give 2 mole AlCl3
i.e
= 8.46 mole Cl2 gas.
At Standard temperature and pressure:
= (22.4 L/1 mole gas) * (8.46 mole Cl2)
= 190 L chlorine gas
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