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ziro4ka [17]
3 years ago
9

Does the variable increase(1) or decrease(1) under the described conditions?

Chemistry
1 answer:
EastWind [94]3 years ago
5 0

Answer:

Explanation:

Decreasing the volume of a contained gas will increase its pressure, and increasing its volume will decrease its pressure. In fact, if the volume increases by a certain factor, the pressure decreases by the same factor, and vice versa. Volume-pressure data for an air sample at room temperature are graphed in Figure 5.

Because the volume has decreased, the particles will collide more frequently with the walls of the container. ... When the volume decreases, the pressure increases. This shows that the pressure of a gas is inversely proportional to its volume. This is shown by the following equation - which is often called Boyle's law.

The kinetic energy of the gas molecules increases, so collisions with the walls of the container are now more forceful than they were before. As a result, the pressure of the gas doubles. Decreasing the temperature would have the opposite effect, and the pressure of an enclosed gas would decrease.

For a fixed mass of gas at constant temperature, the volume is inversely proportional to the pressure. That means that, for example, if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.

Temperature, pressure, volume and the amount of a gas influence its pressure.

Gay Lussac's Law - states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. If you heat a gas you give the molecules more energy so they move faster. This means more impacts on the walls of the container and an increase in the pressure.

i really hope some of this helped i would put more but its a lot too type

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We are given the following information:

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The final volume of the air is:

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$$\begin{aligned}\frac{P_{2} V_{2}}{T_{2}} &=\frac{P_{1} V_{1}}{T_{1}} \\\Rightarrow P_{2} &=\frac{V_{1}}{V_{2}} \times \frac{T_{2}}{T_{1}} \times P_{1} \\&=\frac{V_{1}}{102 V_{1} / 100} \times \frac{319 \mathrm{~K}}{295 \mathrm{~K}} \times 35.0 \mathrm{psi} \\& \approx 37.1 \mathrm{psi}\end{aligned}$$

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Learn more about combined gas law brainly.com/question/13154969

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