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Jobisdone [24]
3 years ago
10

During a reaction, the enthalpy of formation of an intermediate is 90.3 kJ/mol. During the reaction, 2 moles of the intermediate

are formed as a reactant. What is the enthalpy value for this step of the reaction?
A. -180.6 kJ

B. 90.3 kJ

C. -90.3 kJ

D. 180.6 kJ​
Chemistry
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

180.6 kJ​

Explanation:

The enthalpy of reaction refers to the energy absorbed or released during a reaction. If heat is absorbed in a reaction, the enthalpy of reaction is positive. If heat is released in a reaction, the enthalpy of reaction his negative.

Since the energy absorbed when one mole of the intermediate is formed is 90.3 kJ/mol, then, when two moles of intermediate is formed, 2 × 90.3 kJ/mol = 180.6 kJ​ of energy is absorbed.

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B = (2.953 × 10⁻⁹⁵) N.m⁹

Explanation:

At equilibrium, where the distance between the two ions (ro) is the sum of their ionic radii, the force between the two ions is zero.

That is,

Fa + Fr = 0

Fa = - Fr

Fa = (|q₁q₂|)/(4πε₀r²)

Fr = -B/(r^n) but n = 9

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B = (k × |q₁q₂| × r⁷)

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3 years ago
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