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White raven [17]

2 years ago

13

Standing and holding a barbell that has a mass of 100kg at a height of 2m involves being done on the barbell to maintain

1 answer:

expeople1 [14]2 years ago

3 0

Answer:

I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2

Explanation:

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If you live in a very cold area, you may have seen the depth of a bank of snow shrink even though temperatures remain below the

Aleks04 [339]

<span>To answer the question above, if the day sky is clear it collects radiation. If air is dry snow sublimates faster. If both cases overlap it disappears faster where ever coldest. Thank you for posting your question here. I hope my answer helps. </span>

7 0

2 years ago

A 2.0-kg ball rolls to the right at 3.0 m/s. A 4.0-kg ball rolls to the left at 2.0 m/s . What is the momentum of the system aft

charle [14.2K]

Answer:

Final momentum after a head on collision is -2kgm/s

Explanation:

One ball moves to the right and the other moves opposite and momentum is a vector quantity so that considering the direction

Initial momenta are P₁=2x3=6kgm/s P₂=4x(-2)=-8kgm/s

Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s

4 0

2 years ago

What is the SI unit for graviational potential energy

scZoUnD [109]

Gravitational potential energy is energy.
The unit of energy is the Joule.

1 Joule = 1 kilogram-meter² / sec²

3 0

3 years ago

Why is the teammate bond often so strong?

Kazeer [188]

Answer:

c

Explanation:

While people are working, they need to have a strong bond with their teammates,to face all the hardships .

thus, teammates work together, win and lose together, and often eat and live together.

3 0

2 years ago

Read 2 more answers

A long, straight, horizontal wire carries a left-to-right current of 40 A. If the wire is placed in a uniform magnetic field of

sladkih [1.3K]

Answer:

The magnitude of the resultant of the magnetic field is $4.11\times10^{-5}\ T$

Explanation:

Given that,

Current = 40 A

Magnetic field $B=3.7\times10^{-5}\ T$

Distance = 22 cm

We need to calculate the magnetic field

Using formula of magnetic field

$B'=\dfrac{\mu_{0}I}{2\pi r}$

Where, r = distance

I = current

Put the value into the formula

$B'=\dfrac{4\pi\times10^{-7}\times20}{2\pi\times0.22}$

$B'=1.8\times10^{-5}\ T$

We need to calculate the magnitude of the resultant of the magnetic field

Using formula of resultant

$B''=\sqrt{B^2+B'^2}$

Put the value into the formula

$B''=\sqrt{(3.7\times10^{-5})^2+(1.8\times10^{-5})^2}$

$B''=4.11\times10^{-5}\ T$

Hence, The magnitude of the resultant of the magnetic field is $4.11\times10^{-5}\ T$

6 0

2 years ago