Why: As the steel ball rolls uphill, the velocity gradually decreases and finally the ball stops, thus, the acceleration will be in the opposite direction of motion (that is downhill). After the stop, the ball will start rolling downhill by an increasing velocity, thus, the acceleration in this case will be in the same direction as the motion (downhill again).
B) 48.0 m/s
We can actually start to solve the problem from B for simplicity.
The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

where
is the final velocity
is the initial velocity (positive since we take downward as positive direction)
is the acceleration of gravity
s = 110 m is the vertical displacement
Solving for v, we find the final velocity (and so, the speed of the rock at impact):

A) 3.67 s
Now we can find the time of flight of the rock by using the following suvat equation

where
is the final velocity at the moment of impact
is the initial velocity
is the acceleration of gravity
t is the time it takes for the rock to reach the ground
And solving for t, we find

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Answer:
0.031 m
Explanation:
Density of copper = ρ = 8960 kg/m³
r = Radius = 0.262 m
m = Mass of plate = 61.5 kg
v = Volume of plate = Volume of cylinder = πr²h

So, thickness of plate is 0.031 m