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Sedbober [7]
3 years ago
14

1: Give one word answer.

Physics
1 answer:
sammy [17]3 years ago
8 0

Answer:

RThe answer is Reflection....

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If the electric field of an electromagnetic wave is in the x-direction and the magnetic field of the wave is in the y-direction,
Ulleksa [173]

Answer:

Positive z-direction

Explanation:

According to Fleming's right hand rule, point the fingers of your right hand in the direction of Electric field E ( positive x-direction), and curl your fingers toward magnetic field B (positive y-direction), and your thumb points in the direction of propagation of wave (positive z-direction).

Therefore, the correct option will be positive z-direction.

3 0
3 years ago
A 425-g piece of metal at 100°C is dropped into a 100-g aluminum cup containing 500 g of water at 15°C. The final temperature of
yKpoI14uk [10]

The specific heat of the metal, assuming no heat is exchanged with the surroundings is 2140 J/(kg•K).

<h3>Specific heat capacity of the metal</h3>

The specific heat capacity of the metal is determined from the principle of conservation of energy.

energy lost by the metal = energy gained by aluminum + energy gained by water

Q = mcΔθ

where;

  • m is mass (kg)
  • c is specific heat capacity
  • Δθ is change in temperature

0.425c(100 - 40) = 0.1(900)(40 - 15) + 0.5(4186)(40 - 15)

25.5c = 2250 + 52,325

c = 54,575/25.5

c = 2140 J/(kg•K)

Learn more about specific heat capacity here: brainly.com/question/21406849

#SPJ1

5 0
2 years ago
Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml
Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of  electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}

Put the value into the formula

E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}

E=2.41\times10^{3}\ V/m

Hence, The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

3 0
4 years ago
A rock dropped from a 20 meter bridge falls into the river below. How long did it take to reach the water? What velocity did it
Brut [27]

Answer:

2 s, -20 m/s

Explanation:

Given:

y₀ = 20 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t and v

y = y₀ + v₀ t + ½ at²

0 = 20 + 0 + ½ (-9.8) t²

0 = 20 − 4.9 t²

t ≈ 2 s

v² = v₀² + 2a(y − y₀)

v² = 0 + 2(-9.8)(0 − 20)

v ≈ ±20 m/s

Since the rock is falling, v = -20 m/s.

6 0
4 years ago
Identify the technologies that utilize electromagnetism. (Choose 2) Kitchen blender, silicon microchip, inclined plane, electric
Sav [38]

Answer: Kitchen blender and electric drill

Explanation:

8 0
3 years ago
Read 2 more answers
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