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Umnica [9.8K]
2 years ago
11

assume you mix 0.71g of chlorine with 1.00g of fluorine in a 258 ml flask at 23 . what is the partial pressure of each gas

Chemistry
1 answer:
Mice21 [21]2 years ago
6 0

Answer:

See explanation

Explanation:

Number of moles of Cl2 = 0.71g/71g/mol = 0.01 moles

Number of moles = 1.0 g/38g/mol = 0.02 moles

Total = 0.01 + 0.02 = 0.03 moles

From the ideal gas equation;

PV=nRT

P=?

V= 258 ml

n= 0.03 moles

T= 296 K

P= nRT/ V

P= 0.03 × 0.082 × 296/258

P= 0.003 atm

Partial pressure Cl2 = 0.01/0.03 × 0.003 atm = 0.001 atm

Partial pressure = F2 = 0.02/0.03 × 0.003atm = 0.002 atm

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Answer :

(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon and hydrogen respectively.

We are given:

Mass of CO_2=3.381g

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We know that:

Molar mass of carbon dioxide = 44 g/mol

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For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, \frac{12}{44}\times 3.381=0.922g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.692 g of water, \frac{2}{18}\times 0.692=0.0769g of hydrogen will be contained.

Thus, 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) Now we have to determine the compound contain any other elements or not.

Mass carbon + Mass of hydrogen = 0.922 g + 0.0769 g = 0.999 g ≈ 1 g

This means that there is no other element present in the compound.

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